∫Calc Practice

Antiderivatives with initial conditions

Problem 3.628 · medium

Solve the initial-value problem \( \displaystyle f'(x) = -1 + \frac{1}{x^{2}} \), \( \displaystyle f(1) = -2 \).
  1. \[ \frac{d}{d x} \left(- x - \frac{1}{x}\right) = -1 + \frac{1}{x^{2}} \]
    An antiderivative; every other differs by a constant C.✓ Proved
  2. \[ - \left. - x - 1 \frac{1}{x} \right|_{\substack{ x=1 }} - 2 = 0 \]
    f(1) = -2 fixes C.✓ Proved
  3. \[ - x - 1 \frac{1}{x} = - x - \frac{1}{x} \]
    The solution.✓ Proved
Answer \( f(x) = - x - \frac{1}{x} \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the answer differentiated back to the given derivative, and the initial values checked

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the general antiderivative and verifies that the specific constant satisfies the initial condition. The logic is sound.
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-13
  • qwen3.6:27b-mlx: pass 2026-10-13 — The solution correctly identifies the general antiderivative and verifies that the specific constant satisfies the initial condition. The logic is sound.
  • gpt-oss:20b: pass 2026-10-13
  • qwen3.6:27b-mlx: pass 2026-10-13 — The solution correctly identifies the general antiderivative and verifies that the specific constant satisfies the initial condition. The logic is sound and the final answer is correct.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/antiderivative_ivp, checked 2026-10-13 with SymPy 1.14.0.