The Mean Value Theorem and Rolle's theorem
Problem 3.503 · medium
Verify that \( \displaystyle f(x) = - 2 x^{2} - 2 x + 2 \) satisfies the hypotheses of the Mean Value Theorem on \( \displaystyle [1, 5] \), and find every number \( \displaystyle c \) the theorem guarantees.
- f is a polynomial, so it is continuous on [a, b] and differentiable on (a, b): the hypotheses hold.
- \[ - \frac{\left. - 2 x^{2} - 2 x + 2 \right|_{\substack{ x=1 }}}{4} + \frac{\left. - 2 x^{2} - 2 x + 2 \right|_{\substack{ x=5 }}}{4} = -14 \]The slope of the secant line.✓ Proved
- \[ \frac{d}{d x} \left(- 2 x^{2} - 2 x + 2\right) = - 4 x - 2 \]Differentiate.✓ Proved
- \[ -14 \]c = 3 solves f′(c) = -14 and lies in (1, 5).✓ Proved
Answer \( c = 3 \)
Lines: 3 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Not checked | — | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | each c checked by a difference quotient; a scan of (a, b) finds no others |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: fail (error) — The calculation of the secant slope is incorrect; the actual slope is -12, not -14. Consequently, the value c=3 is incorrect (the correct value is c=2.5).
Every verdict on record (4)
qwen3.6:27b-mlx: fail (error) 2026-10-08 — The calculation of the secant slope is incorrect; the actual slope is -12, not -14. Consequently, the value c=3 is incorrect (the correct value is c=2.5).gpt-oss:20b: pass 2026-10-08gpt-oss:20b: pass 2026-10-08qwen3.6:27b-mlx: fail (error) 2026-10-08 — The calculation of the secant slope in step 2 is incorrect; the formula used divides by 4 instead of the interval length (5-1=4) but the numerator calculation is also wrong or the division is misapplied, resulting in -14 instead of the correct slope -12. Consequently, the derived value c=3 is incorrect (the correct value is c=2.5).
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/mean_value_theorem, checked 2026-10-08 with SymPy 1.14.0.