Antiderivatives with initial conditions
Problem 3.484 · hard
Solve \( \displaystyle f''(x) = 3 x^{2} - \frac{2}{x^{2}} \) with \( \displaystyle f'(1) = 3 \) and \( \displaystyle f(1) = 1 \).
- \[ \frac{d}{d x} \left(x^{3} + \frac{2}{x}\right) = 3 x^{2} - \frac{2}{x^{2}} \]An antiderivative of f″; f′ is this plus a constant C₁.✓ Proved
- \[ 3 - \left. x^{3} + \frac{2}{x} \right|_{\substack{ x=1 }} = 0 \]f′(1) = 3 fixes C₁.✓ Proved
- \[ \frac{d}{d x} \left(\frac{x^{4}}{4} + 2 \ln{\left(x \right)}\right) = x^{3} + \frac{2}{x} \]Antidifferentiate f′; add a constant C₀.✓ Proved
- \[ 1 - \left. \frac{x^{4}}{4} + 2 \ln{\left(x \right)} \right|_{\substack{ x=1 }} = \frac{3}{4} \]f(1) = 1 fixes C₀.✓ Proved
- \[ \frac{x^{4}}{4} + 2 \ln{\left(x \right)} + \frac{3}{4} \]The solution.✓ Proved
Answer \( f(x) = \frac{x^{4}}{4} + 2 \ln{\left(x \right)} + \frac{3}{4} \)
Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the answer differentiated back to the given derivative, and the initial values checked |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass
Every verdict on record (4)
gpt-oss:20b: pass 2026-10-07qwen3.6:27b-mlx: pass 2026-10-07gpt-oss:20b: pass 2026-10-07qwen3.6:27b-mlx: fail (error) 2026-10-07 — The antiderivative of -2/x^2 is 2/x, but the solution incorrectly uses 2 ln(x) in the final answer and in step 3. Step 3 claims the derivative of 2 log(x) is 2/x, which does not match the required term 2/x from step 1. The correct term should be 2/x, not 2 ln(x).
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/antiderivative_ivp, checked 2026-10-07 with SymPy 1.14.0.