∫Calc Practice

The Mean Value Theorem and Rolle's theorem

Problem 3.402 · medium

Verify that \( \displaystyle f(x) = - 2 x^{2} + 3 x - 4 \) satisfies the hypotheses of the Mean Value Theorem on \( \displaystyle [-1, 3] \), and find every number \( \displaystyle c \) the theorem guarantees.
  1. f is a polynomial, so it is continuous on [a, b] and differentiable on (a, b): the hypotheses hold.
    Reviewed
  2. \[ - \frac{\left. - 2 x^{2} + 3 x - 4 \right|_{\substack{ x=-1 }}}{4} + \frac{\left. - 2 x^{2} + 3 x - 4 \right|_{\substack{ x=3 }}}{4} = -1 \]
    The slope of the secant line.✓ Proved
  3. \[ \frac{d}{d x} \left(- 2 x^{2} + 3 x - 4\right) = 3 - 4 x \]
    Differentiate.✓ Proved
  4. \[ -1 \]
    c = 1 solves f′(c) = -1 and lies in (-1, 3).✓ Proved
Answer \( c = 1 \)

Lines: 3 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0each c checked by a difference quotient; a scan of (a, b) finds no others

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the hypotheses for the Mean Value Theorem, calculates the average rate of change, sets up the equation f'(c) = m, and verifies the solution lies within the interval.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-04 — The solution correctly identifies the hypotheses for the Mean Value Theorem, calculates the average rate of change, sets up the equation f'(c) = m, and verifies the solution lies within the interval.
  • gpt-oss:20b: pass 2026-10-04
  • qwen3.6:27b-mlx: fail (error) 2026-10-04 — The calculation of the secant slope in step 2 is incorrect; it divides by 4 instead of the interval length (3 - (-1) = 4) but applies the formula incorrectly or uses wrong values, resulting in -1 instead of the correct slope -5. Consequently, the derived value c=1 is incorrect.
  • gpt-oss:20b: pass 2026-10-04

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/mean_value_theorem, checked 2026-10-04 with SymPy 1.14.0.