∫Calc Practice

Antiderivatives with initial conditions

Problem 3.376 · hard

Solve \( \displaystyle f''(x) = x^{3} - 4 \sin{\left(x \right)} \) with \( \displaystyle f'(1) = 6 \) and \( \displaystyle f(1) = 1 \).
  1. \[ \frac{d}{d x} \left(\frac{x^{4}}{4} + 4 \cos{\left(x \right)}\right) = x^{3} - 4 \sin{\left(x \right)} \]
    An antiderivative of f″; f′ is this plus a constant C₁.✓ Proved
  2. \[ 6 - \left. \frac{x^{4}}{4} + 4 \cos{\left(x \right)} \right|_{\substack{ x=1 }} = \frac{23}{4} - 4 \cos{\left(1 \right)} \]
    f′(1) = 6 fixes C₁.✓ Proved
  3. \[ \frac{d}{d x} \left(\frac{x^{5}}{20} - 4 x \cos{\left(1 \right)} + \frac{23 x}{4} + 4 \sin{\left(x \right)}\right) = \frac{x^{4}}{4} + 4 \cos{\left(x \right)} - 4 \cos{\left(1 \right)} + \frac{23}{4} \]
    Antidifferentiate f′; add a constant C₀.✓ Proved
  4. \[ 1 - \left. \frac{x^{5}}{20} - 4 x \cos{\left(1 \right)} + \frac{23 x}{4} + 4 \sin{\left(x \right)} \right|_{\substack{ x=1 }} = - \frac{24}{5} - 4 \sin{\left(1 \right)} + 4 \cos{\left(1 \right)} \]
    f(1) = 1 fixes C₀.✓ Proved
  5. \[ \frac{x^{5}}{20} - 4 x \cos{\left(1 \right)} + \frac{23 x}{4} + 4 \sin{\left(x \right)} - \frac{24}{5} - 4 \sin{\left(1 \right)} + 4 \cos{\left(1 \right)} \]
    The solution.✓ Proved
Answer \( f(x) = \frac{x^{5}}{20} - 4 x \cos{\left(1 \right)} + \frac{23 x}{4} + 4 \sin{\left(x \right)} - \frac{24}{5} - 4 \sin{\left(1 \right)} + 4 \cos{\left(1 \right)} \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the answer differentiated back to the given derivative, and the initial values checked

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-04
  • gpt-oss:20b: pass 2026-10-04
  • qwen3.6:27b-mlx: pass 2026-10-04
  • gpt-oss:20b: pass 2026-10-04

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/antiderivative_ivp, checked 2026-10-04 with SymPy 1.14.0.