∫Calc Practice

Increasing, decreasing and concavity

Problem 3.214 · medium

For \( \displaystyle f(x) = x^{3} - 3 x^{2} - 9 x \), find the intervals where f is increasing or decreasing, where it is concave up or down, and its inflection points.
  1. \[ \frac{d}{d x} \left(x^{3} - 3 x^{2} - 9 x\right) = \left(x + 1\right) \left(3 x - 9\right) \]
    f' factored.✓ Proved
  2. f' > 0 outside [-1, 3] and f' < 0 between them (a positive quadratic with roots -1, 3).
    Reviewed
  3. \[ \frac{d^{2}}{d x^{2}} \left(x^{3} - 3 x^{2} - 9 x\right) = 6 x - 6 \]
    f''.✓ Proved
  4. \[ \left. 6 x - 6 \right|_{\substack{ x=1 }} = 0 \]
    f'' = 0 at x = 1, where it changes sign.✓ Proved
  5. f'' < 0 to the left of 1 (concave down) and f'' > 0 to the right (concave up).
    Reviewed
Answer \( \uparrow (-\infty,-1) \cup (3,\infty);\ \downarrow (-1,3);\ \text{concave down } (-\infty,1),\ \text{up } (1,\infty);\ \text{inflection at } x=1 \)

✓ Nihil obstat Lines: 3 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
5Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the signs of f' and f'' were evaluated at a point inside each interval

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the critical points and inflection point, and accurately determines the signs of the first and second derivatives to establish intervals of increase/decrease and concavity.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly identifies the critical points and inflection point, and accurately determines the signs of the first and second derivatives to establish intervals of increase/decrease and concavity.
  • gpt-oss:20b: pass 2026-09-26
  • qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly identifies the critical points and inflection point, and accurately determines the signs of the first and second derivatives to establish intervals of increase/decrease and concavity.
  • gpt-oss:20b: pass 2026-09-26

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/increasing_concavity, checked 2026-09-26 with SymPy 1.14.0.