∫Calc Practice

Absolute extrema on a closed interval

Problem 3.202 · hard

Find the absolute maximum and minimum values of \( \displaystyle f(x) = - x^{3} + \frac{3 x^{2}}{2} + 18 x + 3 \) on \( \displaystyle [-3, 3] \).
  1. A continuous function on a closed interval has its extreme values at critical points or endpoints.
  2. \[ \frac{d}{d x} \left(- x^{3} + \frac{3 x^{2}}{2} + 18 x + 3\right) = \left(9 - 3 x\right) \left(x + 2\right) \]
    Differentiate and factor.✓ Proved
  3. Critical numbers inside [-3, 3]: -2.
  4. \[ \left. - x^{3} + \frac{3 x^{2}}{2} + 18 x + 3 \right|_{\substack{ x=-3 }} = - \frac{21}{2} \]
    f(-3).✓ Proved
  5. \[ \left. - x^{3} + \frac{3 x^{2}}{2} + 18 x + 3 \right|_{\substack{ x=-2 }} = -19 \]
    f(-2).✓ Proved
  6. \[ \left. - x^{3} + \frac{3 x^{2}}{2} + 18 x + 3 \right|_{\substack{ x=3 }} = \frac{87}{2} \]
    f(3).✓ Proved
  7. The largest value is 87/2 and the smallest is -19.
Answer \( \text{max } \frac{87}{2} \text{ at } x=3;\ \text{min } -19 \text{ at } x=-2 \)

Lines: 4 proved, 3 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1Not checked—a sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3Not checked—a sentence; read, not computed
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
6✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
7Not checked—a sentence; read, not computed
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0f sampled at 40,001 points across the interval reaches the same max and min

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: inconclusive — reviewer returned a non-object
Every verdict on record (4)
  • qwen3.6:27b-mlx: inconclusive 2026-09-26 — reviewer returned a non-object
  • gpt-oss:20b: pass 2026-09-26
  • qwen3.6:27b-mlx: fail (error) 2026-09-26 — The solution fails to evaluate the function at the endpoint x = -3, which is a critical point (f'(-3)=0). Although the final numerical answer for the minimum is coincidentally correct (since f(-2) < f(-3)), the method is flawed because it omits a required candidate for the absolute extrema.
  • gpt-oss:20b: pass 2026-09-26

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/absolute_extrema, checked 2026-09-26 with SymPy 1.14.0.