Optimization
Problem 3.172 · medium
A farmer has 80 m of fencing to enclose a rectangular pen. What dimensions maximize the area, and what is the maximum area?
- Let the sides be x and y. Then 2x + 2y = 80, so y = 40 − x, and the area is A(x) = x(40 − x) for 0 < x < 40.
- \[ \frac{d}{d x} x \left(40.0 - x\right) = 40.0 - 2 x \]A'(x).✓ Proved
- \[ \left. 40.0 - 2 x \right|_{\substack{ x=20.0 }} = 0 \]A'(x) = 0 at x = 20.0000000000000.✓ Proved
- \[ \frac{d^{2}}{d x^{2}} x \left(40.0 - x\right) = -2 \]A'' < 0, so this is a maximum.✓ Proved
- \[ \left. x \left(40.0 - x\right) \right|_{\substack{ x=20.0 }} = 400.0 \]A square 20.0000000000000 m by 20.0000000000000 m.✓ Proved
Answer \( 400.0 \)
Lines: 4 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The explanation has not been reviewed yet.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Not checked | — | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the objective sampled at 200,001 points of its interval tops out at the same value |
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/optimization, checked 2026-09-26 with SymPy 1.14.0.