∫Calc Practice

Linear approximation

Problem 3.17 · easy

Use the linear approximation of \( \displaystyle f(x) = \sqrt{x} \) at \( \displaystyle x = 49 \) to estimate \( \displaystyle f(\frac{249}{5}) \).
  1. The linearization at a is L(x) = f(a) + f'(a)(x − a).
  2. \[ \left. \sqrt{x} \right|_{\substack{ x=49 }} = 7 \]
    f(a).✓ Proved
  3. \[ \left. \frac{d}{d x} \sqrt{x} \right|_{\substack{ x=49 }} = \frac{1}{14} \]
    f'(a).✓ Proved
  4. \[ \frac{x}{14} + \frac{7}{2} \]
    The linearization.✓ Proved
  5. \[ \frac{247}{35} \]
    Evaluate at x = \frac{249}{5}.✓ Proved
Answer \( L(\frac{249}{5}) = \frac{247}{35} \approx 7.05714 \)

Lines: 4 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The explanation has not been reviewed yet.

The full receipt
LineStatusChecked byDetail
1Not checked—a sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the estimate is within Taylor's error bound of the true value

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/linear_approximation, checked 2026-09-26 with SymPy 1.14.0.