Derivative of \( \displaystyle \ln{\left(\cos{\left(x \right)} - 1 \right)} - \ln{\left(\cos{\left(x \right)} + 1 \right)} \)
Problem 2.970 · hard Beautiful
Differentiate \( \displaystyle f(x) = \ln{\left(\cos{\left(x \right)} - 1 \right)} - \ln{\left(\cos{\left(x \right)} + 1 \right)} \).
- \[ \frac{d}{d x} \left(\ln{\left(\cos{\left(x \right)} - 1 \right)} - \ln{\left(\cos{\left(x \right)} + 1 \right)}\right) \]Start with the derivative of the function.✓ Proved
- \[ = \frac{d}{d x} \ln{\left(\cos{\left(x \right)} - 1 \right)} - \frac{d}{d x} \ln{\left(\cos{\left(x \right)} + 1 \right)} \]sumApply the sum rule for subtraction.✓ Proved
- \[ = \frac{d}{d x} \ln{\left(\cos{\left(x \right)} - 1 \right)} + \frac{d}{d x} \left(- \ln{\left(\cos{\left(x \right)} + 1 \right)}\right) \]algebraRewrite the subtraction as addition of a negative.✓ Proved
- \[ = \frac{d}{d x} \ln{\left(\cos{\left(x \right)} - 1 \right)} - \frac{d}{d x} \ln{\left(\cos{\left(x \right)} + 1 \right)} \]constantThe constant factor -1 is moved out.✓ Proved
- \[ = - \frac{\frac{d}{d x} \left(\cos{\left(x \right)} + 1\right)}{\cos{\left(x \right)} + 1} + \frac{\frac{d}{d x} \left(\cos{\left(x \right)} - 1\right)}{\cos{\left(x \right)} - 1} \]chainApply the chain rule to both logarithmic terms.✓ Proved
- \[ = - \frac{\frac{d}{d x} \cos{\left(x \right)}}{\cos{\left(x \right)} + 1} + \frac{\frac{d}{d x} \cos{\left(x \right)}}{\cos{\left(x \right)} - 1} \]derivativeDifferentiate the inner functions (cos(x) - 1) and (cos(x) + 1).✓ Proved
- \[ = \frac{\sin{\left(x \right)}}{\cos{\left(x \right)} + 1} - \frac{\sin{\left(x \right)}}{\cos{\left(x \right)} - 1} \]trig algebraThe derivative of cos(x) is -sin(x). Simplify the signs.✓ Proved
- \[ = \left(\frac{1}{\cos{\left(x \right)} + 1} - \frac{1}{\cos{\left(x \right)} - 1}\right) \sin{\left(x \right)} \]algebraFactor out sin(x).✓ Proved
- \[ = - \frac{2 \sin{\left(x \right)}}{\left(\cos{\left(x \right)} - 1\right) \left(\cos{\left(x \right)} + 1\right)} \]algebraCombine the fractions using a common denominator.✓ Proved
- \[ = - \frac{2 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)} - 1} \]algebra algebraSimplify the numerator and denominator. Distribute sin(x).✓ Proved
- \[ = \frac{2}{\sin{\left(x \right)}} \]algebra simplifyUse the identity cos(x)**2 - 1 = -sin(x)**2. Simplify the expression by canceling -sin(x).✓ Proved
- \[ = 2 \csc{\left(x \right)} \]simplifyRewrite 1/sin(x) as csc(x).✓ Proved
Answer \( \frac{2}{\sin{\left(x \right)}} \)
Mind the domain. The answer is also defined at points where f(x) is not. Substituting there gives a number that is not a slope of f.
Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where cos(x) + 1 = 0 undefined where cos(x) - 1 = 0 |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where cos(x) + 1 = 0 undefined where cos(x) - 1 = 0 |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where cos(x) + 1 = 0 undefined where cos(x) - 1 = 0 |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where cos(x) + 1 = 0 undefined where cos(x) - 1 = 0 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where cos(x) + 1 = 0 undefined where cos(x) - 1 = 0 |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where cos(x) + 1 = 0 undefined where cos(x) - 1 = 0 |
| 11 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where cos(x) + 1 = 0 undefined where cos(x) - 1 = 0 undefined where cos(x)**2 - 1 = 0 |
| 12 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where cos(x)**2 - 1 = 0 |
| 13 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where cos(x)**2 - 1 = 0 undefined where sin(x) = 0 |
| 14 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where sin(x) = 0 |
| 15 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where sin(x) = 0 csc has poles at multiples of pi |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 undefined where sin(x) = 0 |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: fail (error) — Step 5 applies the chain rule to both terms simultaneously, violating the one-rule-per-step constraint. Additionally, Step 4 is logically flawed: it claims to move a constant factor out (which would require the constant-multiple rule) but the expression remains a subtraction, effectively doing nothing or mislabeling the operation.
Every verdict on record (4)
qwen3.6:27b-mlx: fail (error) 2026-09-27 — Step 5 applies the chain rule to both terms simultaneously, violating the one-rule-per-step constraint. Additionally, Step 4 is logically flawed: it claims to move a constant factor out (which would require the constant-multiple rule) but the expression remains a subtraction, effectively doing nothing or mislabeling the operation.gpt-oss:20b: pass 2026-09-27qwen3.6:27b-mlx: pass 2026-09-27gpt-oss:20b: pass 2026-09-27
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-09-27 with SymPy 1.14.0.