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Derivative of \( \displaystyle \frac{5 x^{2} \left(1 - 2 \ln{\left(5 x \right)}\right)}{4} \)

Problem 2.961 · hard

Differentiate \( \displaystyle f(x) = \frac{5 x^{2} \left(1 - 2 \ln{\left(5 x \right)}\right)}{4} \).
  1. \[ \frac{d}{d x} \frac{5 x^{2} \left(1 - 2 \ln{\left(5 x \right)}\right)}{4} \]
    Start with the derivative of the function.✓ Proved
  2. \[ = \frac{5 \frac{d}{d x} x^{2} \left(1 - 2 \ln{\left(5 x \right)}\right)}{4} \]
    constant-multiplePull out the constant factor 5/4.✓ Proved
  3. \[ = \frac{5 x^{2} \frac{d}{d x} \left(1 - 2 \ln{\left(5 x \right)}\right)}{4} + \frac{5 \left(1 - 2 \ln{\left(5 x \right)}\right) \frac{d}{d x} x^{2}}{4} \]
    productApply the product rule.✓ Proved
  4. \[ = \frac{5 x^{2} \frac{d}{d x} \left(1 - 2 \ln{\left(5 x \right)}\right)}{4} + \frac{5 x \left(1 - 2 \ln{\left(5 x \right)}\right)}{2} \]
    derivativeDifferentiate the first part of the product.✓ Proved
  5. \[ = \frac{5 x^{2} \left(\frac{d}{d x} 1 - 2 \frac{d}{d x} \ln{\left(5 x \right)}\right)}{4} + \frac{5 x \left(1 - 2 \ln{\left(5 x \right)}\right)}{2} \]
    sumDifferentiate the second part of the product.✓ Proved
  6. \[ = - \frac{5 x^{2} \frac{d}{d x} \ln{\left(5 x \right)}}{2} + \frac{5 x \left(1 - 2 \ln{\left(5 x \right)}\right)}{2} \]
    derivativeDifferentiate the terms inside the parenthesis.✓ Proved
  7. \[ = \frac{5 x \left(1 - 2 \ln{\left(5 x \right)}\right)}{2} - \frac{x \frac{d}{d x} 5 x}{2} \]
    derivativeApply the chain rule to the logarithm.✓ Proved
  8. \[ = \frac{5 x \left(1 - 2 \ln{\left(5 x \right)}\right)}{2} - \frac{5 x}{2} \]
    derivative algebra algebraDifferentiate the inner function 5*x. Simplify the derivative of the inner function. Simplify the term x**2 * (2/x).✓ Proved
  9. \[ = - 5 x \ln{\left(5 x \right)} \]
    algebra simplify simplifyDistribute 2*x into the parenthesis. Combine like terms. Final simplification.✓ Proved
Answer \( - 5 x \ln{\left(5 x \right)} \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
11✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
12✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
13✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-09-27
  • gpt-oss:20b: pass 2026-09-27
  • qwen3.6:27b-mlx: fail (style) 2026-09-27 — Step 5 is labeled 'sum' but applies the linearity of the derivative operator (specifically constant-multiple and sum rules) to split the derivative of a difference; 'sum' is not a differentiation rule in the provided vocabulary, and 'constant-multiple' or 'derivative' would be more appropriate depending on granularity. Additionally, Step 7 is labeled 'derivative' but explicitly performs the chain rule expansion, which should be labeled 'chain'.
  • gpt-oss:20b: pass 2026-09-27

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-09-27 with SymPy 1.14.0.