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Second derivatives

Problem 2.926 · easy

Find \( \displaystyle \dfrac{d^2y}{dx^2} \) for \( \displaystyle y = \sqrt{x^{2} + 2 x + 1} \).
  1. \[ \frac{d}{d x} \sqrt{x^{2} + 2 x + 1} = \frac{x + 1}{\sqrt{x^{2} + 2 x + 1}} \]
    The first derivative.✓ Proved
  2. \[ \frac{d}{d x} \frac{x + 1}{\sqrt{x^{2} + 2 x + 1}} = 0 \]
    Differentiate again.✓ Proved
Answer \( 0 \)

Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0matches a second difference quotient of f at x = 0.7

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: fail (error) — The solution incorrectly assumes the derivative of the simplified expression is 0 everywhere, ignoring that the original function simplifies to |x+1|, which is not differentiable at x = -1. The second derivative does not exist at x = -1, so stating it is 0 is incorrect.
Every verdict on record (4)
  • qwen3.6:27b-mlx: fail (error) 2026-09-26 — The solution incorrectly assumes the derivative of the simplified expression is 0 everywhere, ignoring that the original function simplifies to |x+1|, which is not differentiable at x = -1. The second derivative does not exist at x = -1, so stating it is 0 is incorrect.
  • gpt-oss:20b: pass 2026-09-26
  • qwen3.6:27b-mlx: fail (style) 2026-09-26 — [domain objection, downgraded to style] The solution incorrectly simplifies the function to y = x + 1, ignoring that sqrt(x^2 + 2x + 1) = |x + 1|. The derivative is undefined at x = -1 and the second derivative is 0 only for x != -1, but the step claiming the second derivative is identically 0 without addressing the absolute value or the point of non-differentiability is mathematically flawed.
  • gpt-oss:20b: inconclusive 2026-09-26 — reviewer response could not be parsed: {"verdict":"fail","severity":"error","notes":"The second derivative is not zero for all x. Since \(y=\sqrt{(x+1)^2}=|x+1|\), the first derivative is \(\operatorname{sgn}(x+1)\), which is \(1\) for \(

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/second_derivative, checked 2026-09-26 with SymPy 1.14.0.