Tangent lines
Problem 2.913 · medium
Find an equation of the tangent line to \( \displaystyle y = 2 x - 2 \sin{\left(x \right)} + 1 \) at \( \displaystyle x = \frac{\pi}{2} \).
- The tangent line passes through the point (a, f(a)) and has slope f'(a).
- \[ \left. 2 x - 2 \sin{\left(x \right)} + 1 \right|_{\substack{ x=\frac{\pi}{2} }} = -1 + \pi \]The point of tangency.✓ Proved
- \[ \frac{d}{d x} \left(2 x - 2 \sin{\left(x \right)} + 1\right) = 2 - 2 \cos{\left(x \right)} \]Differentiate.✓ Proved
- \[ \left. 2 - 2 \cos{\left(x \right)} \right|_{\substack{ x=\frac{\pi}{2} }} = 2 \]The slope at the point.✓ Proved
- \[ 2 x - 1 \]Point-slope form, then simplify.✓ Proved
Answer \( y = 2 x - 1 \)
Lines: 4 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Not checked | — | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the line meets the curve at x = a, and its slope matches a central difference quotient of f there |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: fail (error) — The solution fails to explicitly calculate the tangent line equation using the point-slope formula y - y1 = m(x - x1). Step 5 jumps directly to the final answer '2*x - 1' without showing the substitution of the point (pi/2, pi - 1) and slope 2, making the derivation opaque and potentially confusing for a student.
Every verdict on record (4)
qwen3.6:27b-mlx: fail (error) 2026-09-26 — The solution fails to explicitly calculate the tangent line equation using the point-slope formula y - y1 = m(x - x1). Step 5 jumps directly to the final answer '2*x - 1' without showing the substitution of the point (pi/2, pi - 1) and slope 2, making the derivation opaque and potentially confusing for a student.gpt-oss:20b: pass 2026-09-26qwen3.6:27b-mlx: fail (error) 2026-09-26 — The final equation is incorrect. The point of tangency is (pi/2, pi - 1) and the slope is 2, so the tangent line is y - (pi - 1) = 2(x - pi/2), which simplifies to y = 2x - pi + 1. The solution incorrectly states the equation is y = 2x - 1.gpt-oss:20b: pass 2026-09-26
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/tangent_line, checked 2026-09-26 with SymPy 1.14.0.