∫Calc Practice
Home›Calculus 1›Chain rule›Problem 2.899

Derivative of \( \displaystyle \frac{\sqrt{\left(2 x + 1\right)^{2} + 1}}{2} \)

Problem 2.899 · medium Video

Differentiate \( \displaystyle f(x) = \frac{\sqrt{\left(2 x + 1\right)^{2} + 1}}{2} \).
  1. \[ \frac{d}{d x} \frac{\sqrt{\left(2 x + 1\right)^{2} + 1}}{2} \]
    Start with the derivative of the function.✓ Proved
  2. \[ = \frac{\frac{d}{d x} \sqrt{\left(2 x + 1\right)^{2} + 1}}{2} \]
    constant-multiple rewritePull out the constant factor 1/2. Rewrite the square root as a power.✓ Proved
  3. \[ = \frac{\frac{d}{d x} \left(\left(2 x + 1\right)^{2} + 1\right)}{4 \sqrt{\left(2 x + 1\right)^{2} + 1}} \]
    chainApply the chain rule.✓ Proved
  4. \[ = \frac{\frac{d}{d x} \left(2 x + 1\right)^{2}}{4 \sqrt{\left(2 x + 1\right)^{2} + 1}} \]
    sumDifferentiate the sum inside the parenthesis.✓ Proved
  5. \[ = \frac{\left(4 x + 2\right) \frac{d}{d x} \left(2 x + 1\right)}{4 \sqrt{\left(2 x + 1\right)^{2} + 1}} \]
    powerApply the power rule to the squared term.✓ Proved
  6. \[ = \frac{8 x + 4}{4 \sqrt{\left(2 x + 1\right)^{2} + 1}} \]
    derivative algebraDifferentiate the linear term. Multiply the constants.✓ Proved
  7. \[ = \frac{2 x + 1}{\sqrt{\left(2 x + 1\right)^{2} + 1}} \]
    simplifySimplify the final expression.✓ Proved
Answer \( \frac{2 x + 1}{\sqrt{\left(2 x + 1\right)^{2} + 1}} \)
Top: the graph of f = sqrt((2x + 1)² + 1)/2. A tangent line slides along it, and its slope is plotted below as it goes, tracing f' = (4x + 2)/(2sqrt((2x + 1)² + 1)).

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where (2*x + 1)**2 + 1 = 0
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where (2*x + 1)**2 + 1 = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where (2*x + 1)**2 + 1 = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where (2*x + 1)**2 + 1 = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where (2*x + 1)**2 + 1 = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where (2*x + 1)**2 + 1 = 0
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
undefined where (2*x + 1)**2 + 1 = 0
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: fail (error) — Step 5 applies the sum rule but drops the derivative of the constant 1. The correct derivative of ((2*x + 1)**2 + 1) is 2*(2*x + 1)*2 + 0, so the constant term must be retained (though it vanishes).
  • qwen3.6:27b-mlx: pass

Senior review claude-sonnet-5-5, 2026-10-13: pass — Every line was proved equivalent by SymPy and the rule labels are legitimate. Step 5 correctly applies the sum rule, with the constant's zero derivative absorbed. Line 8 turns 2*(2x+1)*2 into 4*(2x+1), which is a fair algebra step.

  • gpt-oss:20b: dismiss — Dropping the derivative of the constant 1 is part of the sum-rule step, since d/dx(1)=0 is trivially absorbed. Line 5 is equal to line 4 (SymPy proved it), and the objection also misstates the step, because the 2*(2x+1)*2 expansion happens in later lines.
Every verdict on record (7)
  • claude-sonnet-5-5: pass 2026-10-13 — Every line was proved equivalent by SymPy and the rule labels are legitimate. Step 5 correctly applies the sum rule, with the constant's zero derivative absorbed. Line 8 turns 2*(2x+1)*2 into 4*(2x+1), which is a fair algebra step.
  • qwen3.6:27b-mlx: pass 2026-09-27
  • gpt-oss:20b: fail (error) 2026-09-27 — Step 5 applies the sum rule but drops the derivative of the constant 1. The correct derivative of ((2*x + 1)**2 + 1) is 2*(2*x + 1)*2 + 0, so the constant term must be retained (though it vanishes).
  • qwen3.6:27b-mlx: pass 2026-09-26
  • gpt-oss:20b: fail (error) 2026-09-26 — Step 5 drops the derivative of the constant term +1. The sum rule should produce Derivative((2*x+1)**2, x)+Derivative(1, x), but the latter is zero and was omitted, violating the one‑rule‑per‑step rule.
  • qwen3.6:27b-mlx: pass 2026-09-26
  • gpt-oss:20b: pass 2026-09-26

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-09-27 with SymPy 1.14.0.