∫Calc Practice

Implicit differentiation

Problem 2.800 · medium

The curve \( \displaystyle 3 x^{2} + 2 x y + y^{2} = 1 \) passes through \( \displaystyle (0, 1) \). Find \( \displaystyle \dfrac{dy}{dx} \) by implicit differentiation, and its value at that point.
  1. \[ 1 \]
    The point is on the curve.✓ Proved
  2. Differentiate both sides with respect to x, treating y as a function of x, then solve for dy/dx.
  3. \[ \frac{d}{d x} \left(3 x^{2} + 2 x Y{\left(x \right)} + Y^{2}{\left(x \right)}\right) = 6 x + \left(2 x + 2 Y{\left(x \right)}\right) \frac{d}{d x} Y{\left(x \right)} + 2 Y{\left(x \right)} \]
    Every y term picks up a factor dy/dx.✓ Proved
  4. \[ \frac{- 6 x - 2 y}{2 x + 2 y} = \frac{- 3 x - y}{x + y} \]
    Solve for dy/dx: minus F_x over F_y.✓ Proved
  5. \[ -1 \]
    At the point.✓ Proved
Answer \( \frac{dy}{dx} = \frac{- 3 x - y}{x + y}, \quad \left.\frac{dy}{dx}\right|_{(0,1)} = -1 \)

Lines: 4 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The explanation has not been reviewed yet.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Not checked—a sentence; read, not computed
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0sympy.idiff differentiates the curve on its own and agrees

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/implicit_differentiation, checked 2026-09-26 with SymPy 1.14.0.