Derivative of \( \displaystyle \ln{\left(2 \sqrt{x^{2} + 1} \right)} \)
Problem 2.724 · hard Beautiful
Differentiate \( \displaystyle f(x) = \ln{\left(2 \sqrt{x^{2} + 1} \right)} \).
- \[ \frac{d}{d x} \ln{\left(2 \sqrt{x^{2} + 1} \right)} \]derivativeStart with the derivative of the function.✓ Proved
- \[ = \frac{d}{d x} \left(\ln{\left(\sqrt{x^{2} + 1} \right)} + \ln{\left(2 \right)}\right) \]algebra algebraUse the logarithm product rule to split the terms. Rewrite the square root as a fractional power.✓ Proved
- \[ = \frac{d}{d x} \ln{\left(2 \right)} + \frac{d}{d x} \ln{\left(\sqrt{x^{2} + 1} \right)} \]sumApply the sum rule for derivatives.✓ Proved
- \[ = \frac{d}{d x} \ln{\left(\sqrt{x^{2} + 1} \right)} \]constant rewriteThe derivative of the constant log(2) is zero. Rewrite the power using the exponential and logarithm identity.✓ Proved
- \[ = \frac{d}{d x} \frac{\ln{\left(x^{2} + 1 \right)}}{2} \]chainApply the chain rule to the composition of functions.✓ Proved
- \[ = \frac{\frac{d}{d x} \ln{\left(x^{2} + 1 \right)}}{2} \]constant-multiplePull out the constant factor.✓ Proved
- \[ = \frac{\frac{d}{d x} \left(x^{2} + 1\right)}{2 \left(x^{2} + 1\right)} \]chainApply the chain rule to the logarithm.✓ Proved
- \[ = \frac{\frac{d}{d x} 1 + \frac{d}{d x} x^{2}}{2 \left(x^{2} + 1\right)} \]sumApply the sum rule to the inner function.✓ Proved
- \[ = \frac{x}{x^{2} + 1} \]derivative constant simplifyDifferentiate the terms inside the parentheses. The derivative of the constant 1 is zero. Simplify the final expression by canceling the 2.✓ Proved
Answer \( \frac{x}{x^{2} + 1} \)
Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where x**2 + 1 = 0 |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 |
| 11 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 |
| 12 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 |
| 13 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: fail (style) — Step 7 is labeled 'chain' but performs the simplification of log(exp(u)) to u, which is an algebraic/rewrite step, not the application of the chain rule for differentiation. The chain rule is correctly applied in Step 9.
Every verdict on record (4)
qwen3.6:27b-mlx: fail (style) 2026-09-21 — Step 7 is labeled 'chain' but performs the simplification of log(exp(u)) to u, which is an algebraic/rewrite step, not the application of the chain rule for differentiation. The chain rule is correctly applied in Step 9.gpt-oss:20b: pass 2026-09-21qwen3.6:27b-mlx: fail (error) 2026-09-21 — Step 7 is labeled 'chain' but performs a logarithmic simplification (log(a^b) = b*log(a)), which is an algebraic rewrite, not a differentiation step. The chain rule is applied in Step 9.gpt-oss:20b: pass 2026-09-21
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-09-26 with SymPy 1.14.0.