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Derivative of \( \displaystyle \ln{\left(2 \sqrt{x^{2} + 1} \right)} \)

Problem 2.724 · hard Beautiful

Differentiate \( \displaystyle f(x) = \ln{\left(2 \sqrt{x^{2} + 1} \right)} \).
  1. \[ \frac{d}{d x} \ln{\left(2 \sqrt{x^{2} + 1} \right)} \]
    derivativeStart with the derivative of the function.✓ Proved
  2. \[ = \frac{d}{d x} \left(\ln{\left(\sqrt{x^{2} + 1} \right)} + \ln{\left(2 \right)}\right) \]
    algebra algebraUse the logarithm product rule to split the terms. Rewrite the square root as a fractional power.✓ Proved
  3. \[ = \frac{d}{d x} \ln{\left(2 \right)} + \frac{d}{d x} \ln{\left(\sqrt{x^{2} + 1} \right)} \]
    sumApply the sum rule for derivatives.✓ Proved
  4. \[ = \frac{d}{d x} \ln{\left(\sqrt{x^{2} + 1} \right)} \]
    constant rewriteThe derivative of the constant log(2) is zero. Rewrite the power using the exponential and logarithm identity.✓ Proved
  5. \[ = \frac{d}{d x} \frac{\ln{\left(x^{2} + 1 \right)}}{2} \]
    chainApply the chain rule to the composition of functions.✓ Proved
  6. \[ = \frac{\frac{d}{d x} \ln{\left(x^{2} + 1 \right)}}{2} \]
    constant-multiplePull out the constant factor.✓ Proved
  7. \[ = \frac{\frac{d}{d x} \left(x^{2} + 1\right)}{2 \left(x^{2} + 1\right)} \]
    chainApply the chain rule to the logarithm.✓ Proved
  8. \[ = \frac{\frac{d}{d x} 1 + \frac{d}{d x} x^{2}}{2 \left(x^{2} + 1\right)} \]
    sumApply the sum rule to the inner function.✓ Proved
  9. \[ = \frac{x}{x^{2} + 1} \]
    derivative constant simplifyDifferentiate the terms inside the parentheses. The derivative of the constant 1 is zero. Simplify the final expression by canceling the 2.✓ Proved
Answer \( \frac{x}{x^{2} + 1} \)

Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x**2 + 1 = 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 + 1 = 0
11✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 + 1 = 0
12✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 + 1 = 0
13✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 + 1 = 0
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
undefined where x**2 + 1 = 0
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: fail (style) — Step 7 is labeled 'chain' but performs the simplification of log(exp(u)) to u, which is an algebraic/rewrite step, not the application of the chain rule for differentiation. The chain rule is correctly applied in Step 9.
Every verdict on record (4)
  • qwen3.6:27b-mlx: fail (style) 2026-09-21 — Step 7 is labeled 'chain' but performs the simplification of log(exp(u)) to u, which is an algebraic/rewrite step, not the application of the chain rule for differentiation. The chain rule is correctly applied in Step 9.
  • gpt-oss:20b: pass 2026-09-21
  • qwen3.6:27b-mlx: fail (error) 2026-09-21 — Step 7 is labeled 'chain' but performs a logarithmic simplification (log(a^b) = b*log(a)), which is an algebraic rewrite, not a differentiation step. The chain rule is applied in Step 9.
  • gpt-oss:20b: pass 2026-09-21

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-09-26 with SymPy 1.14.0.