Derivative of \( \displaystyle 5 x \ln{\left(2 x - 1 \right)} - 5 x - \frac{5 \ln{\left(2 x - 1 \right)}}{2} \)
Problem 2.51 · hard
Differentiate \( \displaystyle f(x) = 5 x \ln{\left(2 x - 1 \right)} - 5 x - \frac{5 \ln{\left(2 x - 1 \right)}}{2} \).
- \[ \frac{d}{d x} \left(5 x \ln{\left(2 x - 1 \right)} - 5 x - \frac{5 \ln{\left(2 x - 1 \right)}}{2}\right) \]derivativeStart with the derivative of the function.✓ Proved
- \[ = - \frac{d}{d x} 5 x + \frac{d}{d x} 5 x \ln{\left(2 x - 1 \right)} - \frac{d}{d x} \frac{5 \ln{\left(2 x - 1 \right)}}{2} \]sumApply the sum rule to separate the terms.✓ Proved
- \[ = - \frac{d}{d x} 5 x + \frac{d}{d x} 5 x \ln{\left(2 x - 1 \right)} - \frac{5 \frac{d}{d x} \ln{\left(2 x - 1 \right)}}{2} \]constant-multiplePull out the constant factor from the third term.✓ Proved
- \[ = - \frac{d}{d x} 5 x + 5 \frac{d}{d x} x \ln{\left(2 x - 1 \right)} - \frac{5 \frac{d}{d x} \ln{\left(2 x - 1 \right)}}{2} \]constant-multiplePull out the constant factor from the first term.✓ Proved
- \[ = 5 x \frac{d}{d x} \ln{\left(2 x - 1 \right)} + 5 \ln{\left(2 x - 1 \right)} \frac{d}{d x} x - \frac{d}{d x} 5 x - \frac{5 \frac{d}{d x} \ln{\left(2 x - 1 \right)}}{2} \]productApply the product rule to the first term.✓ Proved
- \[ = 5 x \frac{d}{d x} \ln{\left(2 x - 1 \right)} + 5 \ln{\left(2 x - 1 \right)} - \frac{d}{d x} 5 x - \frac{5 \frac{d}{d x} \ln{\left(2 x - 1 \right)}}{2} \]derivativeDifferentiate x.✓ Proved
- \[ = 5 x \frac{d}{d x} \ln{\left(2 x - 1 \right)} + 5 \ln{\left(2 x - 1 \right)} - \frac{5 \frac{d}{d x} \ln{\left(2 x - 1 \right)}}{2} - 5 \]derivative algebraDifferentiate 5*x. Distribute the 5 into the parentheses.✓ Proved
- \[ = \left(5 x - \frac{5}{2}\right) \frac{d}{d x} \ln{\left(2 x - 1 \right)} + 5 \ln{\left(2 x - 1 \right)} - 5 \]algebraGroup the terms involving the derivative of the logarithm.✓ Proved
- \[ = 5 \ln{\left(2 x - 1 \right)} - 5 + \frac{\left(5 x - \frac{5}{2}\right) \frac{d}{d x} \left(2 x - 1\right)}{2 x - 1} \]chainApply the chain rule to the logarithm.✓ Proved
- \[ = 5 \ln{\left(2 x - 1 \right)} - 5 + \frac{2 \left(5 x - \frac{5}{2}\right)}{2 x - 1} \]derivative algebraDifferentiate 2*x - 1. Simplify the expression.✓ Proved
- \[ = 5 \ln{\left(2 x - 1 \right)} - 5 + \frac{10 x - 5}{2 x - 1} \]algebraMultiply the numerator and denominator.✓ Proved
- \[ = 5 \ln{\left(2 x - 1 \right)} \]algebra algebra algebra simplifyCombine the terms over a common denominator. Distribute the -5 in the numerator. Simplify the numerator. Final simplification.✓ Proved
Answer \( 5 \log{\left(2 x - 1 \right)} \)
✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x - 1 = 0 |
| 11 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x - 1 = 0 |
| 12 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x - 1 = 0 |
| 13 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x - 1 = 0 |
| 14 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x - 1 = 0 |
| 15 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 16 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 17 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passdeepseek-r1:70b: passqwen3.6:27b-mlx: pass — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The algebraic simplification in the final steps is valid and leads to the correct result.
Every verdict on record (12)
qwen3.6:27b-mlx: pass 2026-09-20 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The algebraic simplification in the final steps is valid and leads to the correct result.gpt-oss:20b: pass 2026-09-20qwen3.6:27b-mlx: pass 2026-09-20gpt-oss:20b: pass 2026-09-20qwen3.6:27b-mlx: pass 2026-09-19 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The algebraic simplification at the end is valid and leads to the correct result.deepseek-r1:70b: pass 2026-09-19gpt-oss:20b: pass 2026-09-19qwen3.6:27b-mlx: pass 2026-09-19 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The algebraic simplification at the end is valid and leads to the correct result.deepseek-r1:70b: pass 2026-09-19gpt-oss:20b: pass 2026-09-19gpt-oss:20b: inconclusive 2026-09-17 — reviewer response could not be parsed:deepseek-r1:70b: pass 2026-09-17
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-09-26 with SymPy 1.14.0.