Derivative of \( \displaystyle \left(x + \frac{1}{2}\right) e^{2 x + 2} \)
Problem 2.498 · medium
Differentiate \( \displaystyle f(x) = \left(x + \frac{1}{2}\right) e^{2 x + 2} \).
- \[ \frac{d}{d x} \left(x + \frac{1}{2}\right) e^{2 x + 2} \]derivativeStart with the derivative of the function.✓ Proved
- \[ = \frac{d}{d x} x e^{2 x + 2} + \frac{d}{d x} \frac{e^{2 x + 2}}{2} \]sumApply the sum rule.✓ Proved
- \[ = \frac{d}{d x} x e^{2 x + 2} + \frac{\frac{d}{d x} e^{2 x + 2}}{2} \]constant-multiplePull out the constant 1/2.✓ Proved
- \[ = x \frac{d}{d x} e^{2 x + 2} + e^{2 x + 2} \frac{d}{d x} x + \frac{\frac{d}{d x} e^{2 x + 2}}{2} \]productApply the product rule to the first term.✓ Proved
- \[ = x \frac{d}{d x} e^{2 x + 2} + e^{2 x + 2} + \frac{\frac{d}{d x} e^{2 x + 2}}{2} \]derivativeDifferentiate x.✓ Proved
- \[ = x e^{2 x + 2} \frac{d}{d x} \left(2 x + 2\right) + \frac{e^{2 x + 2} \frac{d}{d x} \left(2 x + 2\right)}{2} + e^{2 x + 2} \]chainApply the chain rule to the exponential terms.✓ Proved
- \[ = 2 x e^{2 x + 2} + 2 e^{2 x + 2} \]derivative algebra algebraDifferentiate the inner function 2*x + 2. Simplify the multiplication. Combine like terms.✓ Proved
- \[ = \left(2 x + 2\right) e^{2 x + 2} \]simplifyFactor out the common term.✓ Proved
Answer \( 2 \left(x + 1\right) e^{2 x + 2} \)
✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-09-21gpt-oss:20b: pass 2026-09-21qwen3.6:27b-mlx: pass 2026-09-20gpt-oss:20b: pass 2026-09-20qwen3.6:27b-mlx: pass 2026-09-20gpt-oss:20b: pass 2026-09-20
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-09-26 with SymPy 1.14.0.