∫Calc Practice

Derivative of \( \displaystyle - 5 \ln{\left(\cot{\left(x - 1 \right)} + \csc{\left(x - 1 \right)} \right)} \)

Problem 2.474 · hard Beautiful

Differentiate \( \displaystyle f(x) = - 5 \ln{\left(\cot{\left(x - 1 \right)} + \csc{\left(x - 1 \right)} \right)} \).
  1. \[ \frac{d}{d x} \left(- 5 \ln{\left(\cot{\left(x - 1 \right)} + \csc{\left(x - 1 \right)} \right)}\right) \]
    Start with the derivative of the function.✓ Proved
  2. \[ = - 5 \frac{d}{d x} \ln{\left(\cot{\left(x - 1 \right)} + \csc{\left(x - 1 \right)} \right)} \]
    constant-multiplePull out the constant factor.✓ Proved
  3. \[ = - \frac{5 \frac{d}{d x} \left(\cot{\left(x - 1 \right)} + \csc{\left(x - 1 \right)}\right)}{\cot{\left(x - 1 \right)} + \csc{\left(x - 1 \right)}} \]
    chainApply the chain rule for the logarithm.✓ Proved
  4. \[ = - \frac{5 \left(\frac{d}{d x} \cot{\left(x - 1 \right)} + \frac{d}{d x} \csc{\left(x - 1 \right)}\right)}{\cot{\left(x - 1 \right)} + \csc{\left(x - 1 \right)}} \]
    sumDifferentiate the sum inside the parentheses.✓ Proved
  5. \[ = - \frac{5 \left(- \cot{\left(x - 1 \right)} \csc{\left(x - 1 \right)} \frac{d}{d x} \left(x - 1\right) - \csc^{2}{\left(x - 1 \right)} \frac{d}{d x} \left(x - 1\right)\right)}{\cot{\left(x - 1 \right)} + \csc{\left(x - 1 \right)}} \]
    trigApply the derivative rules for cotangent and cosecant.✓ Proved
  6. \[ = - \frac{5 \left(- \cot{\left(x - 1 \right)} \csc{\left(x - 1 \right)} - \csc^{2}{\left(x - 1 \right)}\right)}{\cot{\left(x - 1 \right)} + \csc{\left(x - 1 \right)}} \]
    derivative algebraDifferentiate the inner linear function x - 1. Simplify the expression.✓ Proved
  7. \[ = \frac{5 \cot{\left(x - 1 \right)} \csc{\left(x - 1 \right)} + 5 \csc^{2}{\left(x - 1 \right)}}{\cot{\left(x - 1 \right)} + \csc{\left(x - 1 \right)}} \]
    algebraDistribute the negative sign and the constant.✓ Proved
  8. \[ = 5 \csc{\left(x - 1 \right)} \]
    algebra simplifyFactor out csc(x - 1) from the numerator. Cancel the common term in the numerator and denominator.✓ Proved
Answer \( \frac{5}{\sin{\left(x - 1 \right)}} \)
Mind the domain. The answer is also defined at points where f(x) is not. Substituting there gives a number that is not a slope of f.

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
csc has poles at multiples of pi
cot has poles at multiples of pi
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where cot(x - 1) + csc(x - 1) = 0
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where cot(x - 1) + csc(x - 1) = 0
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where cot(x - 1) + csc(x - 1) = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where cot(x - 1) + csc(x - 1) = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where cot(x - 1) + csc(x - 1) = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where cot(x - 1) + csc(x - 1) = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where cot(x - 1) + csc(x - 1) = 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
undefined where sin(x - 1) = 0
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-09-21
  • gpt-oss:20b: pass 2026-09-21
  • qwen3.6:27b-mlx: pass 2026-09-20
  • gpt-oss:20b: pass 2026-09-20
  • qwen3.6:27b-mlx: pass 2026-09-20
  • gpt-oss:20b: pass 2026-09-20

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-09-26 with SymPy 1.14.0.