Derivative of \( \displaystyle \frac{e^{2 x}}{2 x} \)
Problem 2.372 · hard
Differentiate \( \displaystyle f(x) = \frac{e^{2 x}}{2 x} \).
- \[ \frac{d}{d x} \frac{e^{2 x}}{2 x} \]rewriteStart with the derivative of the function. Rewrite the denominator using a negative exponent.✓ Proved
- \[ = e^{2 x} \frac{d}{d x} \frac{1}{2 x} + \frac{\frac{d}{d x} e^{2 x}}{2 x} \]productApply the product rule.✓ Proved
- \[ = e^{2 x} \frac{d}{d x} \frac{1}{2 x} + \frac{e^{2 x}}{x} \]chainDifferentiate the exponential term using the chain rule.✓ Proved
- \[ = \frac{e^{2 x}}{x} - \frac{e^{2 x}}{2 x^{2}} \]chain algebra algebra simplifyDifferentiate the power term using the chain rule. Simplify the terms using exponent rules. Simplify the coefficients. Simplify the fraction.✓ Proved
- \[ = \frac{2 x e^{2 x} - e^{2 x}}{2 x^{2}} \]algebraCombine the terms over a common denominator.✓ Proved
- \[ = \frac{\left(2 x - 1\right) e^{2 x}}{2 x^{2}} \]simplifyFactor out the exponential term.✓ Proved
Answer \( \frac{\left(x - \frac{1}{2}\right) e^{2 x}}{x^{2}} \)
✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 undefined where x = 0 |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passdeepseek-r1:70b: fail (error) — Step 1 lacks a rule label, violating the contract.qwen3.6:27b-mlx: pass — The solution correctly applies the product rule and chain rule in separate steps. The algebraic simplifications are valid and lead to the correct final answer.
Every verdict on record (10)
qwen3.6:27b-mlx: pass 2026-09-20 — The solution correctly applies the product rule and chain rule in separate steps. The algebraic simplifications are valid and lead to the correct final answer.gpt-oss:20b: pass 2026-09-20qwen3.6:27b-mlx: pass 2026-09-20gpt-oss:20b: pass 2026-09-20qwen3.6:27b-mlx: pass 2026-09-19deepseek-r1:70b: fail (error) 2026-09-19 — Step 1 lacks a rule label, violating the contract.gpt-oss:20b: pass 2026-09-19qwen3.6:27b-mlx: pass 2026-09-19 — The solution correctly applies the product rule and chain rule in separate steps, adhering to the one-change-per-step constraint. The labels used are appropriate for the operations performed.deepseek-r1:70b: pass 2026-09-19gpt-oss:20b: pass 2026-09-19
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-09-26 with SymPy 1.14.0.