Derivative of \( \displaystyle \frac{x^{2} - 1}{x^{2} + 1} \)
Problem 2.346 · hard
Differentiate \( \displaystyle f(x) = \frac{x^{2} - 1}{x^{2} + 1} \).
- \[ \frac{d}{d x} \frac{x^{2} - 1}{x^{2} + 1} \]derivative rewriteStart with the derivative of the function. Rewrite the quotient as a product using a negative exponent.✓ Proved
- \[ = \left(x^{2} - 1\right) \frac{d}{d x} \frac{1}{x^{2} + 1} + \frac{\frac{d}{d x} \left(x^{2} - 1\right)}{x^{2} + 1} \]productApply the product rule.✓ Proved
- \[ = \frac{2 x}{x^{2} + 1} + \left(x^{2} - 1\right) \frac{d}{d x} \frac{1}{x^{2} + 1} \]derivativeDifferentiate the first part of the product.✓ Proved
- \[ = \frac{2 x}{x^{2} + 1} + \frac{\left(1 - x^{2}\right) \frac{d}{d x} \left(x^{2} + 1\right)}{\left(x^{2} + 1\right)^{2}} \]chainApply the chain rule to the second part.✓ Proved
- \[ = \frac{2 x \left(1 - x^{2}\right)}{\left(x^{2} + 1\right)^{2}} + \frac{2 x}{x^{2} + 1} \]derivativeDifferentiate the inner function of the chain rule.✓ Proved
- \[ = - \frac{2 x \left(x^{2} - 1\right)}{\left(x^{2} + 1\right)^{2}} + \frac{2 x}{x^{2} + 1} \]algebraSimplify the expression by distributing the negative sign and exponents.✓ Proved
- \[ = \frac{- 2 x \left(x^{2} - 1\right) + 2 x \left(x^{2} + 1\right)}{\left(x^{2} + 1\right)^{2}} \]algebraCombine the terms over a common denominator.✓ Proved
- \[ = \frac{4 x}{\left(x^{2} + 1\right)^{2}} \]algebra simplifyExpand the numerator. Combine like terms to get the final answer.✓ Proved
Answer \( \frac{4 x}{\left(x^{2} + 1\right)^{2}} \)
✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passdeepseek-r1:70b: passqwen3.6:27b-mlx: pass — The solution correctly applies the product rule, chain rule, and algebraic simplification steps. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.
Every verdict on record (13)
qwen3.6:27b-mlx: pass 2026-09-20 — The solution correctly applies the product rule, chain rule, and algebraic simplification steps. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.gpt-oss:20b: pass 2026-09-20qwen3.6:27b-mlx: pass 2026-09-20 — The solution correctly applies the product rule, chain rule, and algebraic simplification steps. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.gpt-oss:20b: pass 2026-09-20qwen3.6:27b-mlx: pass 2026-09-19 — The solution correctly applies the product and chain rules, with each step changing only one aspect of the expression. The labels used are appropriate for the operations performed.deepseek-r1:70b: pass 2026-09-19gpt-oss:20b: pass 2026-09-19qwen3.6:27b-mlx: pass 2026-09-19 — The solution correctly applies the product rule, chain rule, and algebraic simplification steps. Each step modifies only one aspect of the expression and uses valid labels from the fixed vocabulary.deepseek-r1:70b: pass 2026-09-19gpt-oss:20b: pass 2026-09-19qwen3.6:27b-mlx: pass 2026-09-18 — The solution correctly applies the product rule, chain rule, and algebraic simplification steps. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.deepseek-r1:70b: pass 2026-09-18gpt-oss:20b: pass 2026-09-18
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-09-26 with SymPy 1.14.0.