∫Calc Practice

Derivative of \( \displaystyle \operatorname{atan}{\left(\left(5 x - 3\right)^{2} \right)} \)

Problem 2.326 · hard

Differentiate \( \displaystyle f(x) = \operatorname{atan}{\left(\left(5 x - 3\right)^{2} \right)} \).
  1. \[ \frac{d}{d x} \operatorname{atan}{\left(\left(5 x - 3\right)^{2} \right)} \]
    rewriteStart with the derivative of the function. Rewrite the power using the exponential and logarithm identity.✓ Proved
  2. \[ = \frac{\frac{d}{d x} \left(5 x - 3\right)^{2}}{\left(5 x - 3\right)^{4} + 1} \]
    chain algebraApply the chain rule for the arctangent function. Simplify the denominator by converting the exponential back to a power.✓ Proved
  3. \[ = \frac{2 \left(5 x - 3\right)^{2} \frac{d}{d x} \ln{\left(5 x - 3 \right)}}{\left(5 x - 3\right)^{4} + 1} \]
    chainApply the chain rule to the numerator.✓ Proved
  4. \[ = \frac{50 x - 30}{\left(5 x - 3\right)^{4} + 1} \]
    chain constant-multiple algebra simplifyDifferentiate the logarithm term using the chain rule. Simplify the constants in the numerator. Convert the exponential back to a power for simplification. Simplify the fraction by canceling the common term (5*x - 3).✓ Proved
Answer \( \frac{50 x - 30}{\left(5 x - 3\right)^{4} + 1} \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where (5*x - 3)**4 + 1 = 0
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where (5*x - 3)**4 + 1 = 0
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where (5*x - 3)**4 + 1 = 0
log is undefined for non-positive arguments
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where (5*x - 3)**4 + 1 = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where (5*x - 3)**4 + 1 = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where (5*x - 3)**4 + 1 = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where (5*x - 3)**4 + 1 = 0
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
undefined where (5*x - 3)**4 + 1 = 0
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: pass
  • deepseek-r1:70b: fail (style) — Step 1 is missing a rule label.
  • qwen3.6:27b-mlx: pass — The solution correctly applies the chain rule and algebraic simplifications. The intermediate rewrite using logarithms is valid and handled correctly in subsequent steps.
Every verdict on record (13)
  • qwen3.6:27b-mlx: pass 2026-09-20 — The solution correctly applies the chain rule and algebraic simplifications. The intermediate rewrite using logarithms is valid and handled correctly in subsequent steps.
  • gpt-oss:20b: pass 2026-09-20
  • qwen3.6:27b-mlx: pass 2026-09-20 — The solution correctly applies the chain rule and algebraic simplifications. Each step isolates a single transformation, and the labels accurately reflect the operations performed.
  • gpt-oss:20b: pass 2026-09-20
  • qwen3.6:27b-mlx: pass 2026-09-19
  • deepseek-r1:70b: fail (style) 2026-09-19 — Step 1 is missing a rule label.
  • gpt-oss:20b: pass 2026-09-19
  • qwen3.6:27b-mlx: pass 2026-09-19
  • deepseek-r1:70b: fail (style) 2026-09-19 — Step 1 lacks a rule label, which is required by the contract.
  • gpt-oss:20b: pass 2026-09-19
  • qwen3.6:27b-mlx: pass 2026-09-18
  • deepseek-r1:70b: pass 2026-09-18
  • gpt-oss:20b: pass 2026-09-18

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-09-26 with SymPy 1.14.0.