Derivative of \( \displaystyle 5 x \ln{\left(4 x - 3 \right)} - 5 x - \frac{15 \ln{\left(4 x - 3 \right)}}{4} \)
Problem 2.294 · hard
Differentiate \( \displaystyle f(x) = 5 x \ln{\left(4 x - 3 \right)} - 5 x - \frac{15 \ln{\left(4 x - 3 \right)}}{4} \).
- \[ \frac{d}{d x} \left(5 x \ln{\left(4 x - 3 \right)} - 5 x - \frac{15 \ln{\left(4 x - 3 \right)}}{4}\right) \]Start with the derivative of the function.✓ Proved
- \[ = - \frac{d}{d x} 5 x + \frac{d}{d x} 5 x \ln{\left(4 x - 3 \right)} - \frac{d}{d x} \frac{15 \ln{\left(4 x - 3 \right)}}{4} \]sumApply the sum rule to differentiate each term separately.✓ Proved
- \[ = \frac{d}{d x} 5 x \ln{\left(4 x - 3 \right)} - \frac{d}{d x} \frac{15 \ln{\left(4 x - 3 \right)}}{4} - 5 \]constantThe derivative of 5*x is 5.✓ Proved
- \[ = 5 x \frac{d}{d x} \ln{\left(4 x - 3 \right)} + \ln{\left(4 x - 3 \right)} \frac{d}{d x} 5 x - \frac{d}{d x} \frac{15 \ln{\left(4 x - 3 \right)}}{4} - 5 \]productApply the product rule to the first term.✓ Proved
- \[ = 5 x \frac{d}{d x} \ln{\left(4 x - 3 \right)} + 5 \ln{\left(4 x - 3 \right)} - \frac{d}{d x} \frac{15 \ln{\left(4 x - 3 \right)}}{4} - 5 \]constant-multipleDifferentiate the first part of the product term.✓ Proved
- \[ = \frac{20 x}{4 x - 3} + 5 \ln{\left(4 x - 3 \right)} - 5 - \frac{15}{4 x - 3} \]chain algebraApply the chain rule to the logarithmic terms. Simplify the products of the constants and the inner derivative.✓ Proved
- \[ = 5 \ln{\left(4 x - 3 \right)} - 5 + \frac{20 x - 15}{4 x - 3} \]algebra algebraCombine the fractions with the same denominator. Factor out 5 from the numerator.✓ Proved
- \[ = 5 \ln{\left(4 x - 3 \right)} \]simplify simplifyCancel the common term (4*x - 3) in the fraction. Combine the remaining constant terms.✓ Proved
Answer \( 5 \log{\left(4 x - 3 \right)} \)
✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 4*x - 3 = 0 |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 4*x - 3 = 0 |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 4*x - 3 = 0 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 4*x - 3 = 0 |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 4*x - 3 = 0 |
| 11 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: fail (style) — Step 5 incorrectly labels the simplification of Derivative(5*x, x) as "constant-multiple"; it should be "constant". No other multi-rule steps are present.deepseek-r1:70b: passqwen3.6:27b-mlx: pass — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The labels used are appropriate for the operations performed, and the algebraic simplification is sound.
Every verdict on record (12)
qwen3.6:27b-mlx: pass 2026-09-20 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The labels used are appropriate for the operations performed, and the algebraic simplification is sound.gpt-oss:20b: fail (style) 2026-09-20 — Step 5 incorrectly labels the simplification of Derivative(5*x, x) as "constant-multiple"; it should be "constant". No other multi-rule steps are present.qwen3.6:27b-mlx: pass 2026-09-20 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The labels used are appropriate for the operations performed.gpt-oss:20b: pass 2026-09-20qwen3.6:27b-mlx: pass 2026-09-19 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The labels used are appropriate for the operations performed.deepseek-r1:70b: pass 2026-09-19gpt-oss:20b: fail (style) 2026-09-19 — Several steps are labeled with the wrong rule. Step 3 applies the derivative rule to 5*x, not the constant rule. Step 5 simplifies the derivative of 5*x to 5, again a derivative step, not a constant‑multiple step. These mislabelings mislead a student about which rule is being used.qwen3.6:27b-mlx: pass 2026-09-19 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The labels used are appropriate for the operations performed.deepseek-r1:70b: fail (style) 2026-09-19 — First step lacks a rule label.gpt-oss:20b: pass 2026-09-19gpt-oss:20b: fail 2026-09-17 — Step 3 incorrectly labels the derivative of 5*x as "constant"; it should be the constant‑multiple rule (derivative of c·x = c).deepseek-r1:70b: pass 2026-09-17
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-09-26 with SymPy 1.14.0.