Derivative of \( \displaystyle - 5 x + \left(5 x + \frac{10}{3}\right) \ln{\left(3 x + 2 \right)} \)
Problem 2.2509 · hard Video
Differentiate \( \displaystyle f(x) = - 5 x + \left(5 x + \frac{10}{3}\right) \ln{\left(3 x + 2 \right)} \).
- \[ \frac{d}{d x} \left(- 5 x + \left(5 x + \frac{10}{3}\right) \ln{\left(3 x + 2 \right)}\right) \]derivativeStart with the derivative of the function.✓ Proved
- \[ = \frac{d}{d x} \left(- 5 x\right) + \frac{d}{d x} \left(5 x + \frac{10}{3}\right) \ln{\left(3 x + 2 \right)} \]sumApply the sum rule.✓ Proved
- \[ = \frac{d}{d x} \left(- 5 x\right) + \frac{d}{d x} 5 x \ln{\left(3 x + 2 \right)} + \frac{d}{d x} \frac{10 \ln{\left(3 x + 2 \right)}}{3} \]productApply the product rule to the second term.✓ Proved
- \[ = \frac{d}{d x} \left(- 5 x\right) + \frac{d}{d x} 5 x \ln{\left(3 x + 2 \right)} + \frac{10 \frac{d}{d x} \ln{\left(3 x + 2 \right)}}{3} \]constant-multipleApply the constant multiple rule to the third term.✓ Proved
- \[ = \frac{d}{d x} 5 x \ln{\left(3 x + 2 \right)} + \frac{10 \frac{d}{d x} \ln{\left(3 x + 2 \right)}}{3} - 5 \]constantDifferentiate the first term.✓ Proved
- \[ = 5 x \frac{d}{d x} \ln{\left(3 x + 2 \right)} + \ln{\left(3 x + 2 \right)} \frac{d}{d x} 5 x + \frac{10 \frac{d}{d x} \ln{\left(3 x + 2 \right)}}{3} - 5 \]productApply the product rule to the second term.✓ Proved
- \[ = 5 x \frac{d}{d x} \ln{\left(3 x + 2 \right)} + 5 \ln{\left(3 x + 2 \right)} + \frac{10 \frac{d}{d x} \ln{\left(3 x + 2 \right)}}{3} - 5 \]constantDifferentiate the first term of the product.✓ Proved
- \[ = \frac{15 x}{3 x + 2} + 5 \ln{\left(3 x + 2 \right)} + \frac{10 \frac{d}{d x} \ln{\left(3 x + 2 \right)}}{3} - 5 \]chainApply the chain rule to the log terms.✓ Proved
- \[ = \frac{15 x}{3 x + 2} + 5 \ln{\left(3 x + 2 \right)} - 5 + \frac{10}{3 x + 2} \]chain algebraApply the chain rule to the third term. Simplify the terms.✓ Proved
- \[ = 5 \ln{\left(3 x + 2 \right)} - 5 + \frac{15 x + 10}{3 x + 2} \]algebra algebraCombine the fractions. Factor the numerator.✓ Proved
- \[ = 5 \ln{\left(3 x + 2 \right)} \]simplify simplifyCancel the common factor. Combine the constant terms.✓ Proved
Answer \( 5 \ln{\left(3 x + 2 \right)} \)
Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 3*x + 2 = 0 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 3*x + 2 = 0 |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 3*x + 2 = 0 |
| 11 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 3*x + 2 = 0 |
| 12 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 3*x + 2 = 0 |
| 13 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 3*x + 2 = 0 |
| 14 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-27gpt-oss:20b: pass 2026-10-27qwen3.6:27b-mlx: pass 2026-10-26 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The algebraic simplifications are valid and clearly labeled.gpt-oss:20b: fail (error) 2026-10-26 — Step 3 incorrectly applies the product rule to the term (5*x + 10/3)*log(3*x + 2). The correct approach is to first rewrite it as 5*x*log(3*x + 2) + (10/3)*log(3*x + 2) (an algebraic split) and then apply the product rule only to the 5*x*log part. The step as written conflates two separate operations into one, violating the single‑rule‑per‑step rule.qwen3.6:27b-mlx: fail (style) 2026-10-26 — Step 3 is labeled 'product' but performs a distribution (algebraic expansion) of the term (5*x + 10/3)*log(...) into a sum, not the product rule differentiation. The product rule is correctly applied in Step 6.gpt-oss:20b: fail (style) 2026-10-26 — Step 3 incorrectly labels a distribution (sum) as a product. The step applies the sum rule, not the product rule, so the rule name is misleading.
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-10-27 with SymPy 1.14.0.