Derivative rules from a table of values
Problem 2.2500 · easy
Use the table to find \( \displaystyle h'(1) \) for \( \displaystyle h(x) = x f(x) + \left[g(x)\right]^{2} \). \[ \begin{array}{c|cccc} x & f(x) & f'(x) & g(x) & g'(x) \\ \hline 1 & 5 & 1 & 1 & 1\end{array} \]
- Product rule on x·f(x), chain rule on g(x)².
- \[ 1 \cdot 1 + 2 \cdot 1 \cdot 1 + 5 = 8 \]Read the values from the table and substitute.✓ Proved
Answer \( h'(1) = 8 \)
Lines: 1 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Not checked | — | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | differentiated concrete polynomials built to match the table |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: fail (error) — The solution fails to explicitly state the derived formula for h'(x) before substituting values. It jumps from naming the rules to a numerical expression, omitting the crucial step of showing that h'(x) = f(x) + x f'(x) + 2 g(x) g'(x). This makes the origin of the terms '1*1', '2*1*1', and '5' opaque and risks teaching students to substitute without understanding the structure of the derivative.
Every verdict on record (6)
qwen3.6:27b-mlx: fail (error) 2026-10-26 — The solution fails to explicitly state the derived formula for h'(x) before substituting values. It jumps from naming the rules to a numerical expression, omitting the crucial step of showing that h'(x) = f(x) + x f'(x) + 2 g(x) g'(x). This makes the origin of the terms '1*1', '2*1*1', and '5' opaque and risks teaching students to substitute without understanding the structure of the derivative.gpt-oss:20b: pass 2026-10-26qwen3.6:27b-mlx: fail (error) 2026-10-25 — The solution fails to explicitly state the derived formula for h'(x) before substituting values. While the arithmetic in line 2 is correct, line 1 only lists rules without showing how they combine into h'(x) = f(x) + x f'(x) + 2g(x)g'(x), making the jump to the numerical expression in line 2 opaque and skipping the crucial modeling step.gpt-oss:20b: pass 2026-10-25qwen3.6:27b-mlx: fail (error) 2026-10-25 — The solution fails to explicitly state the derived formula for h'(x) before substitution, making the arithmetic in step 2 appear unmotivated and obscuring the application of the product and chain rules. Specifically, it skips showing that h'(x) = f(x) + x f'(x) + 2g(x)g'(x), which is necessary to verify that the terms 1*1, 2*1*1, and 5 correspond correctly to the components of the derivative.gpt-oss:20b: pass 2026-10-25
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/derivative_from_table, checked 2026-10-26 with SymPy 1.14.0.