∫Calc Practice

The derivative from the limit definition

Problem 2.2496 · medium Video

Use the limit definition of the derivative to find \( \displaystyle f'(x) \) for \( \displaystyle f(x) = \sqrt{x + 2} \), then find \( \displaystyle f'(1) \).
  1. By definition f′(x) = lim_{h→0} [f(x + h) − f(x)]/h.
    Reviewed
  2. \[ \left. \sqrt{x + 2} \right|_{\substack{ x=h + x }} = \sqrt{h + x + 2} \]
    Write out f(x + h).✓ Proved
  3. \[ \frac{- \sqrt{x + 2} + \sqrt{h + x + 2}}{h} = \frac{1}{\sqrt{x + 2} + \sqrt{h + x + 2}} \]
    Rationalise the numerator and cancel the factor h.✓ Proved
  4. \[ \lim_{h \to 0^+} \frac{1}{\sqrt{x + 2} + \sqrt{h + x + 2}} = \frac{1}{2 \sqrt{x + 2}} \]
    Now h → 0 by direct substitution.✓ Proved
  5. \[ \left. 1 \frac{1}{2 \sqrt{x + 2}} \right|_{\substack{ x=1 }} = \frac{\sqrt{3}}{6} \]
    At x = 1.✓ Proved
Answer \( f'(x) = \frac{1}{2 \sqrt{x + 2}},\ f'(1) = \frac{\sqrt{3}}{6} \)
Top: the graph of f = sqrt(x + 2). A tangent line slides along it, and its slope is plotted below as it goes, tracing f' = 1/(2sqrt(x + 2)).

✓ Nihil obstat Lines: 4 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0matches the derivative by the power, quotient and chain rules

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies the limit definition of the derivative, including the necessary algebraic step of rationalizing the numerator to resolve the 0/0 indeterminate form. The final evaluation is correct.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-10-26 — The solution correctly applies the limit definition of the derivative, including the necessary algebraic step of rationalizing the numerator to resolve the 0/0 indeterminate form. The final evaluation is correct.
  • gpt-oss:20b: pass 2026-10-26
  • qwen3.6:27b-mlx: pass 2026-10-25 — The solution correctly applies the limit definition of the derivative, handles the algebraic simplification (rationalizing the numerator) accurately, and evaluates the limit and specific value correctly.
  • gpt-oss:20b: pass 2026-10-25
  • qwen3.6:27b-mlx: pass 2026-10-25 — The solution correctly applies the limit definition of the derivative, performs the algebraic simplification (rationalizing the numerator) accurately, and evaluates the limit and specific value correctly.
  • gpt-oss:20b: pass 2026-10-25

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/derivative_definition, checked 2026-10-26 with SymPy 1.14.0.