Derivative of \( \displaystyle - \frac{3 x^{2}}{4} + \frac{x}{2} + \left(\frac{3 x^{2}}{2} - x + \frac{1}{6}\right) \ln{\left(3 x - 1 \right)} \)
Problem 2.2440 · hard Video
Differentiate \( \displaystyle f(x) = - \frac{3 x^{2}}{4} + \frac{x}{2} + \left(\frac{3 x^{2}}{2} - x + \frac{1}{6}\right) \ln{\left(3 x - 1 \right)} \).
- \[ \frac{d}{d x} \left(- \frac{3 x^{2}}{4} + \frac{x}{2} + \left(\frac{3 x^{2}}{2} - x + \frac{1}{6}\right) \ln{\left(3 x - 1 \right)}\right) \]derivativeDifferentiate the entire function.✓ Proved
- \[ = \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \left(- \frac{3 x^{2}}{4}\right) + \frac{d}{d x} \left(\frac{3 x^{2}}{2} - x + \frac{1}{6}\right) \ln{\left(3 x - 1 \right)} \]sum constant-multipleApply the sum rule. Factor out the constants.✓ Proved
- \[ = \frac{\frac{d}{d x} x}{2} - \frac{3 \frac{d}{d x} x^{2}}{4} + \frac{d}{d x} \left(\frac{3 x^{2}}{2} - x + \frac{1}{6}\right) \ln{\left(3 x - 1 \right)} \]constant-multipleFactor out the constants from each term.✓ Proved
- \[ = - \frac{3 x}{2} + \frac{d}{d x} \left(\frac{3 x^{2}}{2} - x + \frac{1}{6}\right) \ln{\left(3 x - 1 \right)} + \frac{1}{2} \]powerDifferentiate the power terms.✓ Proved
- \[ = - \frac{3 x}{2} + \left(\frac{3 x^{2}}{2} - x + \frac{1}{6}\right) \frac{d}{d x} \ln{\left(3 x - 1 \right)} + \ln{\left(3 x - 1 \right)} \frac{d}{d x} \left(\frac{3 x^{2}}{2} - x + \frac{1}{6}\right) + \frac{1}{2} \]productApply the product rule to the third term.✓ Proved
- \[ = - \frac{3 x}{2} + \left(- \frac{d}{d x} x + \frac{3 \frac{d}{d x} x^{2}}{2}\right) \ln{\left(3 x - 1 \right)} + \left(\frac{3 x^{2}}{2} - x + \frac{1}{6}\right) \frac{d}{d x} \ln{\left(3 x - 1 \right)} + \frac{1}{2} \]sumDifferentiate the polynomial inside the product rule.✓ Proved
- \[ = - \frac{3 x}{2} + \left(3 x - 1\right) \ln{\left(3 x - 1 \right)} + \left(\frac{3 x^{2}}{2} - x + \frac{1}{6}\right) \frac{d}{d x} \ln{\left(3 x - 1 \right)} + \frac{1}{2} \]power algebraDifferentiate the power terms in the first part of the product rule. Simplify the expression inside the parentheses.✓ Proved
- \[ = - \frac{3 x}{2} + \left(3 x - 1\right) \ln{\left(3 x - 1 \right)} + \frac{1}{2} + \frac{\left(\frac{3 x^{2}}{2} - x + \frac{1}{6}\right) \frac{d}{d x} \left(3 x - 1\right)}{3 x - 1} \]chainApply the chain rule to the logarithm.✓ Proved
- \[ = - \frac{3 x}{2} + \left(3 x - 1\right) \ln{\left(3 x - 1 \right)} + \frac{1}{2} + \frac{3 \left(\frac{3 x^{2}}{2} - x + \frac{1}{6}\right)}{3 x - 1} \]constant-multipleDifferentiate the inner function 3x - 1.✓ Proved
- \[ = - \frac{3 x}{2} + \left(3 x - 1\right) \ln{\left(3 x - 1 \right)} + \frac{1}{2} + \frac{\frac{9 x^{2}}{2} - 3 x + \frac{1}{2}}{3 x - 1} \]algebra simplify algebraMultiply the 3 into the numerator. Simplify the first two terms. Factor out 1/2 from the numerator.✓ Proved
- \[ = \left(3 x - 1\right) \ln{\left(3 x - 1 \right)} \]algebra simplify algebra simplifyRecognize the perfect square trinomial. Cancel the common factor (3x - 1). Distribute the 1/2. Combine all terms to find the final simplified derivative.✓ Proved
Answer \( \left(3 x - 1\right) \ln{\left(3 x - 1 \right)} \)
✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 3*x - 1 = 0 |
| 11 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 3*x - 1 = 0 |
| 12 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 3*x - 1 = 0 |
| 13 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 3*x - 1 = 0 |
| 14 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 3*x - 1 = 0 |
| 15 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 3*x - 1 = 0 |
| 16 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 17 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 18 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly applies differentiation rules and algebraic simplifications in a step-by-step manner. Each step adheres to the single-rule constraint and uses valid labels from the fixed vocabulary.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-19 — The solution correctly applies differentiation rules and algebraic simplifications in a step-by-step manner. Each step adheres to the single-rule constraint and uses valid labels from the fixed vocabulary.gpt-oss:20b: pass 2026-10-19qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. All labels are appropriate for the operations performed, and the algebraic simplifications are valid.gpt-oss:20b: pass 2026-10-17qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly applies differentiation rules and algebraic simplifications in a step-by-step manner. Each step adheres to the single-rule constraint and uses valid labels from the fixed vocabulary.gpt-oss:20b: pass 2026-10-17
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-10-19 with SymPy 1.14.0.