Derivative of \( \displaystyle x - \left(x + \frac{1}{3}\right) \ln{\left(3 x + 1 \right)} \)
Problem 2.2419 · hard Video
Differentiate \( \displaystyle f(x) = x - \left(x + \frac{1}{3}\right) \ln{\left(3 x + 1 \right)} \).
- \[ \frac{d}{d x} \left(x - \left(x + \frac{1}{3}\right) \ln{\left(3 x + 1 \right)}\right) \]derivativeStart with the derivative of the function.✓ Proved
- \[ = \frac{d}{d x} x - \frac{d}{d x} \left(x + \frac{1}{3}\right) \ln{\left(3 x + 1 \right)} \]sumApply the difference rule.✓ Proved
- \[ = - \left(x + \frac{1}{3}\right) \frac{d}{d x} \ln{\left(3 x + 1 \right)} - \ln{\left(3 x + 1 \right)} \frac{d}{d x} \left(x + \frac{1}{3}\right) + \frac{d}{d x} x \]productApply the product rule to the second term.✓ Proved
- \[ = - \left(x + \frac{1}{3}\right) \frac{d}{d x} \ln{\left(3 x + 1 \right)} - \ln{\left(3 x + 1 \right)} \frac{d}{d x} \frac{1}{3} - \ln{\left(3 x + 1 \right)} \frac{d}{d x} x + \frac{d}{d x} x \]sumApply the sum rule to the first term of the product.✓ Proved
- \[ = - \left(x + \frac{1}{3}\right) \frac{d}{d x} \ln{\left(3 x + 1 \right)} - \ln{\left(3 x + 1 \right)} \frac{d}{d x} x + \frac{d}{d x} x \]constant simplifyThe derivative of the constant 1/3 is 0. Simplify the expression by removing the zero term.✓ Proved
- \[ = - \frac{\left(x + \frac{1}{3}\right) \frac{d}{d x} \left(3 x + 1\right)}{3 x + 1} - \ln{\left(3 x + 1 \right)} \frac{d}{d x} x + \frac{d}{d x} x \]chainApply the chain rule to the logarithm.✓ Proved
- \[ = - \frac{3 \left(x + \frac{1}{3}\right)}{3 x + 1} - \ln{\left(3 x + 1 \right)} \frac{d}{d x} x + \frac{d}{d x} x \]chainApply the chain rule to the inner function 3x + 1.✓ Proved
- \[ = - \frac{3 \left(x + \frac{1}{3}\right)}{3 x + 1} - \ln{\left(3 x + 1 \right)} + 1 \]derivativeEvaluate the derivatives of the basic terms.✓ Proved
- \[ = - \ln{\left(3 x + 1 \right)} \]algebra algebra algebra simplifyDistribute the negative sign. Distribute the 3 in the numerator. Simplify the fraction. Combine the constant terms.✓ Proved
Answer \( - \ln{\left(3 x + 1 \right)} \)
✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 3*x + 1 = 0 |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 3*x + 1 = 0 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 3*x + 1 = 0 |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 3*x + 1 = 0 |
| 11 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 12 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 13 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-19gpt-oss:20b: pass 2026-10-19qwen3.6:27b-mlx: fail (style) 2026-10-16 — Step 4 applies the sum rule to the term (x + 1/3) inside the product, but the label 'sum' is ambiguous because the outer structure is still a product; more critically, Step 8 is labeled 'chain' but performs the evaluation of the derivative of the inner function (a 'derivative' step) and simplification, violating the one-rule-per-step constraint by combining chain rule application with basic differentiation and algebraic simplification.gpt-oss:20b: pass 2026-10-16qwen3.6:27b-mlx: fail (style) 2026-10-16 — Step 8 is labeled 'chain', but it evaluates the derivative of the inner function (a basic power/constant rule), which should be labeled 'derivative'. Step 7 correctly labeled the chain rule application to the log structure, so Step 8 is redundant or mislabeled.gpt-oss:20b: pass 2026-10-16
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-10-19 with SymPy 1.14.0.