∫Calc Practice

Derivative of \( \displaystyle x - \left(x + \frac{2}{5}\right) \ln{\left(5 x + 2 \right)} \)

Problem 2.2389 · hard Video

Differentiate \( \displaystyle f(x) = x - \left(x + \frac{2}{5}\right) \ln{\left(5 x + 2 \right)} \).
  1. \[ \frac{d}{d x} \left(x - \left(x + \frac{2}{5}\right) \ln{\left(5 x + 2 \right)}\right) \]
    derivativeStart with the derivative of the function.✓ Proved
  2. \[ = \frac{d}{d x} x - \frac{d}{d x} \left(x + \frac{2}{5}\right) \ln{\left(5 x + 2 \right)} \]
    sumApply the difference rule.✓ Proved
  3. \[ = 1 - \frac{d}{d x} \left(x + \frac{2}{5}\right) \ln{\left(5 x + 2 \right)} \]
    constantThe derivative of x is 1.✓ Proved
  4. \[ = - \left(x + \frac{2}{5}\right) \frac{d}{d x} \ln{\left(5 x + 2 \right)} - \ln{\left(5 x + 2 \right)} \frac{d}{d x} \left(x + \frac{2}{5}\right) + 1 \]
    productApply the product rule to the second term.✓ Proved
  5. \[ = - \left(x + \frac{2}{5}\right) \frac{d}{d x} \ln{\left(5 x + 2 \right)} - \left(\frac{d}{d x} \frac{2}{5} + \frac{d}{d x} x\right) \ln{\left(5 x + 2 \right)} + 1 \]
    sumDistribute the derivative over the sum inside the parentheses.✓ Proved
  6. \[ = - \left(x + \frac{2}{5}\right) \frac{d}{d x} \ln{\left(5 x + 2 \right)} - \ln{\left(5 x + 2 \right)} + 1 \]
    constant algebraThe derivative of the constant 2/5 is 0. Simplify the expression inside the parentheses.✓ Proved
  7. \[ = - \frac{\left(x + \frac{2}{5}\right) \frac{d}{d x} \left(5 x + 2\right)}{5 x + 2} - \ln{\left(5 x + 2 \right)} + 1 \]
    chainApply the chain rule to the logarithm.✓ Proved
  8. \[ = - \frac{5 \left(x + \frac{2}{5}\right)}{5 x + 2} - \ln{\left(5 x + 2 \right)} + 1 \]
    derivativeThe derivative of 5*x + 2 is 5.✓ Proved
  9. \[ = - \ln{\left(5 x + 2 \right)} \]
    algebra algebra simplify algebra simplifyMultiply the terms in the second part of the expression. Distribute the 5 into the numerator. Simplify the fraction. Distribute the negative sign. Final simplification.✓ Proved
Answer \( - \ln{\left(5 x + 2 \right)} \)
Top: the graph of f = x - (x + 2/5)·log(5x + 2). A tangent line slides along it, and its slope is plotted below as it goes, tracing f' = -5(x + 2/5)/(5x + 2) - log(5x + 2) + 1.

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 5*x + 2 = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 5*x + 2 = 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 5*x + 2 = 0
11✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
12✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
13✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
14✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies differentiation rules and algebraic simplifications in a step-by-step manner. Each step changes only one aspect of the expression and uses appropriate labels from the fixed vocabulary.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-10-18 — The solution correctly applies differentiation rules and algebraic simplifications in a step-by-step manner. Each step changes only one aspect of the expression and uses appropriate labels from the fixed vocabulary.
  • gpt-oss:20b: pass 2026-10-18
  • qwen3.6:27b-mlx: pass 2026-10-16 — The solution correctly applies differentiation rules and algebraic simplifications in single-step increments. All labels are appropriate and the logic is sound.
  • gpt-oss:20b: pass 2026-10-16
  • qwen3.6:27b-mlx: pass 2026-10-15 — The solution correctly applies differentiation rules and algebraic simplifications in single-step increments. All labels are appropriate and the logic is sound.
  • gpt-oss:20b: pass 2026-10-15

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-10-18 with SymPy 1.14.0.