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Derivative of \( \displaystyle \frac{x^{2}}{2} + \frac{x}{2} - \left(x^{2} + x + \frac{1}{4}\right) \ln{\left(2 x + 1 \right)} \)

Problem 2.2015 · hard

Differentiate \( \displaystyle f(x) = \frac{x^{2}}{2} + \frac{x}{2} - \left(x^{2} + x + \frac{1}{4}\right) \ln{\left(2 x + 1 \right)} \).
  1. \[ \frac{d}{d x} \left(\frac{x^{2}}{2} + \frac{x}{2} - \left(x^{2} + x + \frac{1}{4}\right) \ln{\left(2 x + 1 \right)}\right) \]
    sumDifferentiate the sum term by term.✓ Proved
  2. \[ = \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{x^{2}}{2} - \frac{d}{d x} \left(x^{2} + x + \frac{1}{4}\right) \ln{\left(2 x + 1 \right)} \]
    sum✓ Proved
  3. \[ = - \left(x^{2} + x + \frac{1}{4}\right) \frac{d}{d x} \ln{\left(2 x + 1 \right)} - \ln{\left(2 x + 1 \right)} \frac{d}{d x} \left(x^{2} + x + \frac{1}{4}\right) + \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{x^{2}}{2} \]
    productApply the product rule to the last term.✓ Proved
  4. \[ = - \left(2 x + 1\right) \ln{\left(2 x + 1 \right)} - \left(x^{2} + x + \frac{1}{4}\right) \frac{d}{d x} \ln{\left(2 x + 1 \right)} + \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{x^{2}}{2} \]
    derivativeDifferentiate the polynomial part.✓ Proved
  5. \[ = - \left(2 x + 1\right) \ln{\left(2 x + 1 \right)} + \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{x^{2}}{2} - \frac{\left(x^{2} + x + \frac{1}{4}\right) \frac{d}{d x} \left(2 x + 1\right)}{2 x + 1} \]
    chainApply the chain rule to the logarithm.✓ Proved
  6. \[ = - \left(2 x + 1\right) \ln{\left(2 x + 1 \right)} + \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{x^{2}}{2} - \frac{2 \left(x^{2} + x + \frac{1}{4}\right)}{2 x + 1} \]
    derivativeDifferentiate the inner function 2x + 1.✓ Proved
  7. \[ = - \left(2 x + 1\right) \ln{\left(2 x + 1 \right)} + \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{x^{2}}{2} - \frac{2 x^{2} + 2 x + \frac{1}{2}}{2 x + 1} \]
    algebraSimplify the fraction.✓ Proved
  8. \[ = x - \left(2 x + 1\right) \ln{\left(2 x + 1 \right)} + \frac{1}{2} - \frac{2 x^{2} + 2 x + \frac{1}{2}}{2 x + 1} \]
    derivative algebraDifferentiate the first two terms. Distribute the negative sign.✓ Proved
  9. \[ = x - \left(2 x + 1\right) \ln{\left(2 x + 1 \right)} + \frac{1}{2} - \frac{4 x^{2} + 4 x + 1}{4 x + 2} \]
    algebraMultiply the numerator and denominator by 2.✓ Proved
  10. \[ = x - \frac{\left(2 x + 1\right)^{2}}{4 x + 2} - \left(2 x + 1\right) \ln{\left(2 x + 1 \right)} + \frac{1}{2} \]
    algebraRecognize the perfect square trinomial.✓ Proved
  11. \[ = - \left(2 x + 1\right) \ln{\left(2 x + 1 \right)} \]
    simplify algebraCancel the common factor (2x + 1). Split the fraction.✓ Proved
  12. \[ = \left(- 2 x - 1\right) \ln{\left(2 x + 1 \right)} \]
    simplifyCombine all remaining terms.✓ Proved
Answer \( \left(- 2 x - 1\right) \ln{\left(2 x + 1 \right)} \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
undefined where 4*x + 2 = 0
11✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 4*x + 2 = 0
12✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 4*x + 2 = 0
13✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
14✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-10
  • qwen3.6:27b-mlx: pass 2026-10-10
  • gpt-oss:20b: pass 2026-10-10
  • qwen3.6:27b-mlx: pass 2026-10-10

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-10-10 with SymPy 1.14.0.