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Home›Calculus 1›Product rule›Problem 2.1756

Derivative of \( \displaystyle - \frac{x^{2}}{2} - \frac{x}{2} + \left(x^{2} + x + \frac{1}{4}\right) \ln{\left(2 x + 1 \right)} \)

Problem 2.1756 · hard

Differentiate \( \displaystyle f(x) = - \frac{x^{2}}{2} - \frac{x}{2} + \left(x^{2} + x + \frac{1}{4}\right) \ln{\left(2 x + 1 \right)} \).
  1. \[ \frac{d}{d x} \left(- \frac{x^{2}}{2} - \frac{x}{2} + \left(x^{2} + x + \frac{1}{4}\right) \ln{\left(2 x + 1 \right)}\right) \]
    derivativeStart with the derivative of the function.✓ Proved
  2. \[ = \frac{d}{d x} \left(- \frac{x}{2}\right) + \frac{d}{d x} \left(- \frac{x^{2}}{2}\right) + \frac{d}{d x} \left(x^{2} + x + \frac{1}{4}\right) \ln{\left(2 x + 1 \right)} \]
    sumApply the sum rule.✓ Proved
  3. \[ = \left(x^{2} + x + \frac{1}{4}\right) \frac{d}{d x} \ln{\left(2 x + 1 \right)} + \ln{\left(2 x + 1 \right)} \frac{d}{d x} \left(x^{2} + x + \frac{1}{4}\right) + \frac{d}{d x} \left(- \frac{x}{2}\right) + \frac{d}{d x} \left(- \frac{x^{2}}{2}\right) \]
    productApply the product rule to the third term.✓ Proved
  4. \[ = \left(2 x + 1\right) \ln{\left(2 x + 1 \right)} + \left(x^{2} + x + \frac{1}{4}\right) \frac{d}{d x} \ln{\left(2 x + 1 \right)} + \frac{d}{d x} \left(- \frac{x}{2}\right) + \frac{d}{d x} \left(- \frac{x^{2}}{2}\right) \]
    derivativeDifferentiate the polynomial part of the product.✓ Proved
  5. \[ = \left(2 x + 1\right) \ln{\left(2 x + 1 \right)} + \frac{d}{d x} \left(- \frac{x}{2}\right) + \frac{d}{d x} \left(- \frac{x^{2}}{2}\right) + \frac{\left(x^{2} + x + \frac{1}{4}\right) \frac{d}{d x} \left(2 x + 1\right)}{2 x + 1} \]
    chainApply the chain rule to the logarithm.✓ Proved
  6. \[ = \left(2 x + 1\right) \ln{\left(2 x + 1 \right)} + \frac{d}{d x} \left(- \frac{x}{2}\right) + \frac{d}{d x} \left(- \frac{x^{2}}{2}\right) + \frac{2 \left(x^{2} + x + \frac{1}{4}\right)}{2 x + 1} \]
    derivativeDifferentiate the inner function of the logarithm.✓ Proved
  7. \[ = - x + \left(2 x + 1\right) \ln{\left(2 x + 1 \right)} - \frac{1}{2} + \frac{2 \left(x^{2} + x + \frac{1}{4}\right)}{2 x + 1} \]
    derivative algebraEvaluate the derivatives of the first two terms. Combine the first two terms.✓ Proved
  8. \[ = - x + \frac{2 \left(x + \frac{1}{2}\right)^{2}}{2 x + 1} + \left(2 x + 1\right) \ln{\left(2 x + 1 \right)} - \frac{1}{2} \]
    algebra algebraRewrite the quadratic term as a square. Factor the denominator.✓ Proved
  9. \[ = \left(2 x + 1\right) \ln{\left(2 x + 1 \right)} \]
    algebra algebra simplifySimplify the fraction. Simplify the remaining term. Combine all terms to get the final result.✓ Proved
Answer \( \left(2 x + 1\right) \ln{\left(2 x + 1 \right)} \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
11✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
12✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
13✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies differentiation rules and algebraic simplifications in single-step increments. The labels accurately reflect the operations performed at each stage.
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-07
  • qwen3.6:27b-mlx: pass 2026-10-07 — The solution correctly applies differentiation rules and algebraic simplifications in single-step increments. The labels accurately reflect the operations performed at each stage.
  • gpt-oss:20b: pass 2026-10-07
  • qwen3.6:27b-mlx: pass 2026-10-07

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-10-07 with SymPy 1.14.0.