Derivative of \( \displaystyle \frac{x^{2}}{2} - \frac{x}{2} + \left(- x^{2} + x - \frac{1}{4}\right) \ln{\left(2 x - 1 \right)} \)
Problem 2.1743 · hard
Differentiate \( \displaystyle f(x) = \frac{x^{2}}{2} - \frac{x}{2} + \left(- x^{2} + x - \frac{1}{4}\right) \ln{\left(2 x - 1 \right)} \).
- \[ \frac{d}{d x} \left(\frac{x^{2}}{2} - \frac{x}{2} + \left(- x^{2} + x - \frac{1}{4}\right) \ln{\left(2 x - 1 \right)}\right) \]derivativeStart with the derivative of the function.✓ Proved
- \[ = - \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{x^{2}}{2} + \frac{d}{d x} \left(- x^{2} + x - \frac{1}{4}\right) \ln{\left(2 x - 1 \right)} \]sumApply the sum rule.✓ Proved
- \[ = \left(- x^{2} + x - \frac{1}{4}\right) \frac{d}{d x} \ln{\left(2 x - 1 \right)} + \ln{\left(2 x - 1 \right)} \frac{d}{d x} \left(- x^{2} + x - \frac{1}{4}\right) - \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{x^{2}}{2} \]productApply the product rule to the third term.✓ Proved
- \[ = \left(1 - 2 x\right) \ln{\left(2 x - 1 \right)} + \left(- x^{2} + x - \frac{1}{4}\right) \frac{d}{d x} \ln{\left(2 x - 1 \right)} - \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{x^{2}}{2} \]derivativeDifferentiate the polynomial part.✓ Proved
- \[ = \left(1 - 2 x\right) \ln{\left(2 x - 1 \right)} - \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{x^{2}}{2} + \frac{\left(- x^{2} + x - \frac{1}{4}\right) \frac{d}{d x} \left(2 x - 1\right)}{2 x - 1} \]chainApply the chain rule to the logarithm.✓ Proved
- \[ = \left(1 - 2 x\right) \ln{\left(2 x - 1 \right)} - \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{x^{2}}{2} + \frac{2 \left(- x^{2} + x - \frac{1}{4}\right)}{2 x - 1} \]derivativeDifferentiate the inner function 2x - 1.✓ Proved
- \[ = \left(1 - 2 x\right) \ln{\left(2 x - 1 \right)} - \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{x^{2}}{2} + \frac{- 2 x^{2} + 2 x - \frac{1}{2}}{2 x - 1} \]algebraSimplify the fraction.✓ Proved
- \[ = x + \left(1 - 2 x\right) \ln{\left(2 x - 1 \right)} - \frac{1}{2} + \frac{- 2 x^{2} + 2 x - \frac{1}{2}}{2 x - 1} \]derivative algebraDifferentiate the first two terms. Distribute the 2 in the numerator.✓ Proved
- \[ = x + \left(1 - 2 x\right) \ln{\left(2 x - 1 \right)} - \frac{1}{2} + \frac{- 4 x^{2} + 4 x - 1}{4 x - 2} \]algebraMultiply numerator and denominator by 2 to clear the fraction.✓ Proved
- \[ = x + \left(1 - 2 x\right) \ln{\left(2 x - 1 \right)} - \frac{1}{2} - \frac{4 x^{2} - 4 x + 1}{4 x - 2} \]algebraFactor out the negative sign.✓ Proved
- \[ = x + \left(1 - 2 x\right) \ln{\left(2 x - 1 \right)} - \frac{\left(2 x - 1\right)^{2}}{4 x - 2} - \frac{1}{2} \]algebraRecognize the perfect square trinomial.✓ Proved
- \[ = \left(1 - 2 x\right) \ln{\left(2 x - 1 \right)} \]algebra algebra simplifyCancel the common factor (2*x - 1). Split the fraction. Combine all terms to get the final answer.✓ Proved
Answer \( \left(1 - 2 x\right) \ln{\left(2 x - 1 \right)} \)
✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x - 1 = 0 |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x - 1 = 0 |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x - 1 = 0 |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x - 1 = 0 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x - 1 = 0 |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x - 1 = 0 undefined where 4*x - 2 = 0 |
| 11 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 4*x - 2 = 0 |
| 12 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 4*x - 2 = 0 |
| 13 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 4*x - 2 = 0 |
| 14 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 15 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly applies differentiation rules and algebraic simplifications in single-step increments. The labels used are appropriate for the operations performed, and the final result matches the stated answer.
Every verdict on record (4)
gpt-oss:20b: pass 2026-10-07qwen3.6:27b-mlx: pass 2026-10-07 — The solution correctly applies differentiation rules and algebraic simplifications in single-step increments. The labels used are appropriate for the operations performed, and the final result matches the stated answer.gpt-oss:20b: pass 2026-10-07qwen3.6:27b-mlx: pass 2026-10-07 — The solution correctly applies differentiation rules and algebraic simplifications in single-step increments. All labels are appropriate for the operations performed.
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-10-07 with SymPy 1.14.0.