∫Calc Practice

Derivative of \( \displaystyle - 2 x + \left(2 x - 6\right) \ln{\left(x - 3 \right)} \)

Problem 2.1504 · hard Beautiful

Differentiate \( \displaystyle f(x) = - 2 x + \left(2 x - 6\right) \ln{\left(x - 3 \right)} \).
  1. \[ \frac{d}{d x} \left(- 2 x + \left(2 x - 6\right) \ln{\left(x - 3 \right)}\right) \]
    Start with the derivative of the function.✓ Proved
  2. \[ = \frac{d}{d x} \left(- 2 x\right) + \frac{d}{d x} \left(2 x - 6\right) \ln{\left(x - 3 \right)} \]
    sumApply the sum rule.✓ Proved
  3. \[ = \left(2 x - 6\right) \frac{d}{d x} \ln{\left(x - 3 \right)} + \ln{\left(x - 3 \right)} \frac{d}{d x} \left(2 x - 6\right) + \frac{d}{d x} \left(- 2 x\right) \]
    productApply the product rule to the second term.✓ Proved
  4. \[ = \left(2 x - 6\right) \frac{d}{d x} \ln{\left(x - 3 \right)} + \ln{\left(x - 3 \right)} \frac{d}{d x} \left(2 x - 6\right) - 2 \]
    constantDifferentiate the first term.✓ Proved
  5. \[ = \left(2 x - 6\right) \frac{d}{d x} \ln{\left(x - 3 \right)} + 2 \ln{\left(x - 3 \right)} - 2 \]
    derivativeDifferentiate the first part of the product rule.✓ Proved
  6. \[ = 2 \ln{\left(x - 3 \right)} - 2 + \frac{2 x - 6}{x - 3} \]
    derivative algebraDifferentiate the logarithm. Factor the term (2*x - 6).✓ Proved
  7. \[ = 2 \ln{\left(x - 3 \right)} \]
    simplify simplifySimplify the fraction. Combine the constant terms.✓ Proved
Answer \( 2 \ln{\left(x - 3 \right)} \)

Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x - 3 = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x - 3 = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x - 3 = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: fail (error) — Step 7 combines factoring of (2*x-6) into 2*(x-3) and cancellation with the denominator in one line, applying two algebraic rules at once, which violates the one‑change‑per‑step rule.
  • qwen3.6:27b-mlx: pass — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The labels used are appropriate for the operations performed.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-04 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The labels used are appropriate for the operations performed.
  • gpt-oss:20b: fail (error) 2026-10-04 — Step 7 combines factoring of (2*x-6) into 2*(x-3) and cancellation with the denominator in one line, applying two algebraic rules at once, which violates the one‑change‑per‑step rule.
  • qwen3.6:27b-mlx: pass 2026-10-04
  • gpt-oss:20b: pass 2026-10-04

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-10-04 with SymPy 1.14.0.