Derivative of \( \displaystyle \frac{\ln{\left(\tan{\left(3 x - 3 \right)} + \sec{\left(3 x - 3 \right)} \right)}}{3} \)
Problem 2.150 · hard
Differentiate \( \displaystyle f(x) = \frac{\ln{\left(\tan{\left(3 x - 3 \right)} + \sec{\left(3 x - 3 \right)} \right)}}{3} \).
- \[ \frac{d}{d x} \frac{\ln{\left(\tan{\left(3 x - 3 \right)} + \sec{\left(3 x - 3 \right)} \right)}}{3} \]Start with the derivative of the function.✓ Proved
- \[ = \frac{\frac{d}{d x} \ln{\left(\tan{\left(3 x - 3 \right)} + \sec{\left(3 x - 3 \right)} \right)}}{3} \]constant-multiplePull out the constant factor 1/3.✓ Proved
- \[ = \frac{\frac{d}{d x} \left(\tan{\left(3 x - 3 \right)} + \sec{\left(3 x - 3 \right)}\right)}{3 \left(\tan{\left(3 x - 3 \right)} + \sec{\left(3 x - 3 \right)}\right)} \]chainApply the chain rule for the logarithm.✓ Proved
- \[ = \frac{\frac{d}{d x} \tan{\left(3 x - 3 \right)} + \frac{d}{d x} \sec{\left(3 x - 3 \right)}}{3 \left(\tan{\left(3 x - 3 \right)} + \sec{\left(3 x - 3 \right)}\right)} \]sumApply the sum rule to the inner expression.✓ Proved
- \[ = \frac{3 \tan{\left(3 x - 3 \right)} \sec{\left(3 x - 3 \right)} + 3 \sec^{2}{\left(3 x - 3 \right)}}{3 \left(\tan{\left(3 x - 3 \right)} + \sec{\left(3 x - 3 \right)}\right)} \]chainDifferentiate the tangent and secant terms using the chain rule.✓ Proved
- \[ = \frac{\tan{\left(3 x - 3 \right)} \sec{\left(3 x - 3 \right)} + \sec^{2}{\left(3 x - 3 \right)}}{\tan{\left(3 x - 3 \right)} + \sec{\left(3 x - 3 \right)}} \]constant-multiple simplifyFactor out the constant 3 from the derivative sum. Cancel the 1/3 and 3, then simplify the expression.✓ Proved
- \[ = \sec{\left(3 x - 3 \right)} \]algebra simplifyFactor out sec(3*x - 3) from the numerator. Cancel the common term in the numerator and denominator.✓ Proved
Answer \( \frac{1}{\cos{\left(3 x - 3 \right)}} \)
Mind the domain. The answer is also defined at points where f(x) is not. Substituting there gives a number that is not a slope of f.
✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(3*x - 3) + sec(3*x - 3) = 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(3*x - 3) + sec(3*x - 3) = 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(3*x - 3) + sec(3*x - 3) = 0 |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(3*x - 3) + sec(3*x - 3) = 0 |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(3*x - 3) + sec(3*x - 3) = 0 |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(3*x - 3) + sec(3*x - 3) = 0 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 sec has poles at odd multiples of pi/2 |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 undefined where cos(3*x - 3) = 0 |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passdeepseek-r1:70b: passqwen3.6:27b-mlx: pass
Every verdict on record (15)
qwen3.6:27b-mlx: pass 2026-09-20gpt-oss:20b: pass 2026-09-20qwen3.6:27b-mlx: pass 2026-09-20gpt-oss:20b: pass 2026-09-20qwen3.6:27b-mlx: pass 2026-09-19deepseek-r1:70b: pass 2026-09-19gpt-oss:20b: pass 2026-09-19qwen3.6:27b-mlx: pass 2026-09-19deepseek-r1:70b: fail (error) 2026-09-19 — Step 1 is missing a rule label, which is required by the contract.gpt-oss:20b: pass 2026-09-19qwen3.6:27b-mlx: pass 2026-09-18deepseek-r1:70b: fail (style) 2026-09-18 — Step 1 is missing a rule label.gpt-oss:20b: pass 2026-09-18gpt-oss:20b: pass 2026-09-17deepseek-r1:70b: pass 2026-09-17
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-09-26 with SymPy 1.14.0.