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Derivative of \( \displaystyle \ln{\left(x + \sqrt{x^{2} + 1} \right)} \)

Problem 2.1476 · hard

Differentiate \( \displaystyle f(x) = \ln{\left(x + \sqrt{x^{2} + 1} \right)} \).
  1. \[ \frac{d}{d x} \ln{\left(x + \sqrt{x^{2} + 1} \right)} \]
    derivativeStart with the derivative of the function.✓ Proved
  2. \[ = \frac{\frac{d}{d x} \left(x + \sqrt{x^{2} + 1}\right)}{x + \sqrt{x^{2} + 1}} \]
    chainApply the chain rule for the logarithm.✓ Proved
  3. \[ = \frac{\frac{d}{d x} x + \frac{d}{d x} \sqrt{x^{2} + 1}}{x + \sqrt{x^{2} + 1}} \]
    sumApply the sum rule to the inner expression.✓ Proved
  4. \[ = \frac{\frac{d}{d x} \sqrt{x^{2} + 1} + 1}{x + \sqrt{x^{2} + 1}} \]
    constant rewriteThe derivative of x is 1. Rewrite the square root as a power.✓ Proved
  5. \[ = \frac{1 + \frac{\frac{d}{d x} \left(x^{2} + 1\right)}{2 \sqrt{x^{2} + 1}}}{x + \sqrt{x^{2} + 1}} \]
    powerApply the power rule.✓ Proved
  6. \[ = \frac{\frac{x}{\sqrt{x^{2} + 1}} + 1}{x + \sqrt{x^{2} + 1}} \]
    derivative constant-multiple rewriteDifferentiate the inner polynomial. Simplify the constant 1/2 * 2. Rewrite the negative power as a reciprocal.✓ Proved
  7. \[ = \frac{1}{\sqrt{x^{2} + 1}} \]
    algebra algebra simplifyFind a common denominator for the numerator. Multiply the numerator by the reciprocal. Cancel the common term (x + sqrt(x**2 + 1)).✓ Proved
Answer \( \frac{1}{\sqrt{x^{2} + 1}} \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x + sqrt(x**2 + 1) = 0
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x + sqrt(x**2 + 1) = 0
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x + sqrt(x**2 + 1) = 0
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x + sqrt(x**2 + 1) = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x + sqrt(x**2 + 1) = 0
undefined where x**2 + 1 = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 + 1 = 0
undefined where x + sqrt(x**2 + 1) = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 + 1 = 0
undefined where x + sqrt(x**2 + 1) = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 + 1 = 0
undefined where x + sqrt(x**2 + 1) = 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 + 1 = 0
undefined where x + sqrt(x**2 + 1) = 0
11✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 + 1 = 0
12✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 + 1 = 0
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
undefined where x**2 + 1 = 0
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-04
  • gpt-oss:20b: pass 2026-10-04
  • qwen3.6:27b-mlx: pass 2026-10-04
  • gpt-oss:20b: pass 2026-10-04

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-10-04 with SymPy 1.14.0.