Derivative of \( \displaystyle - \frac{5 \ln{\left(\tan^{2}{\left(x + 2 \right)} + 1 \right)}}{2} + 5 \ln{\left(\tan{\left(x + 2 \right)} \right)} \)
Problem 2.1449 · hard Beautiful
Differentiate \( \displaystyle f(x) = - \frac{5 \ln{\left(\tan^{2}{\left(x + 2 \right)} + 1 \right)}}{2} + 5 \ln{\left(\tan{\left(x + 2 \right)} \right)} \).
- \[ \frac{d}{d x} \left(- \frac{5 \ln{\left(\tan^{2}{\left(x + 2 \right)} + 1 \right)}}{2} + 5 \ln{\left(\tan{\left(x + 2 \right)} \right)}\right) \]derivativeStart with the derivative of the function.✓ Proved
- \[ = \frac{d}{d x} \left(- \frac{5 \ln{\left(\tan^{2}{\left(x + 2 \right)} + 1 \right)}}{2}\right) + \frac{d}{d x} 5 \ln{\left(\tan{\left(x + 2 \right)} \right)} \]sumApply the sum rule.✓ Proved
- \[ = \frac{d}{d x} \left(- \frac{5 \ln{\left(\tan^{2}{\left(x + 2 \right)} + 1 \right)}}{2}\right) + 5 \frac{d}{d x} \ln{\left(\tan{\left(x + 2 \right)} \right)} \]constant-multipleFactor out the constant from the second term.✓ Proved
- \[ = \frac{5 \frac{d}{d x} \tan{\left(x + 2 \right)}}{\tan{\left(x + 2 \right)}} - \frac{5 \frac{d}{d x} \left(\tan^{2}{\left(x + 2 \right)} + 1\right)}{2 \left(\tan^{2}{\left(x + 2 \right)} + 1\right)} \]logarithmicApply the chain rule for the logarithm.✓ Proved
- \[ = \frac{5 \frac{d}{d x} \tan{\left(x + 2 \right)}}{\tan{\left(x + 2 \right)}} - \frac{5 \left(\frac{d}{d x} 1 + \frac{d}{d x} \tan^{2}{\left(x + 2 \right)}\right)}{2 \left(\tan^{2}{\left(x + 2 \right)} + 1\right)} \]sumApply the sum rule to the inner derivative.✓ Proved
- \[ = \frac{5 \frac{d}{d x} \tan{\left(x + 2 \right)}}{\tan{\left(x + 2 \right)}} - \frac{5 \frac{d}{d x} \tan^{2}{\left(x + 2 \right)}}{2 \left(\tan^{2}{\left(x + 2 \right)} + 1\right)} \]constantThe derivative of a constant is zero.✓ Proved
- \[ = \frac{5 \frac{d}{d x} \tan{\left(x + 2 \right)}}{\tan{\left(x + 2 \right)}} - \frac{5 \tan{\left(x + 2 \right)} \frac{d}{d x} \tan{\left(x + 2 \right)}}{\tan^{2}{\left(x + 2 \right)} + 1} \]powerApply the power rule to the squared term.✓ Proved
- \[ = \frac{5 \sec^{2}{\left(x + 2 \right)}}{\tan{\left(x + 2 \right)}} - \frac{5 \tan{\left(x + 2 \right)} \sec^{2}{\left(x + 2 \right)}}{\tan^{2}{\left(x + 2 \right)} + 1} \]trig algebraSubstitute the derivative of tan(x+2). Simplify the coefficients.≈ Checked numerically
- \[ = \frac{5 \left(\tan^{2}{\left(x + 2 \right)} + 1\right) \sec^{2}{\left(x + 2 \right)} - 5 \tan^{2}{\left(x + 2 \right)} \sec^{2}{\left(x + 2 \right)}}{\left(\tan^{2}{\left(x + 2 \right)} + 1\right) \tan{\left(x + 2 \right)}} \]algebraFind a common denominator.✓ Proved
- \[ = \frac{5 \sec^{2}{\left(x + 2 \right)}}{\left(\tan^{2}{\left(x + 2 \right)} + 1\right) \tan{\left(x + 2 \right)}} \]algebra simplifyDistribute the numerator. Cancel the common terms in the numerator.✓ Proved
- \[ = \frac{5}{\tan{\left(x + 2 \right)}} \]algebra simplifyUse the identity 1 + tan(x)^2 = sec(x)^2. Cancel the sec(x+2)^2 term.≈ Checked numerically
- \[ = 5 \cot{\left(x + 2 \right)} \]trigUse the identity 1/tan(x) = cot(x).✓ Proved
Answer \( \frac{5}{\tan{\left(x + 2 \right)}} \)
Mind the domain. The answer is also defined at points where f(x) is not. Substituting there gives a number that is not a slope of f.
✓ Nihil obstat Lines: 14 proved, 2 checked numerically. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments tan has poles at odd multiples of pi/2 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments tan has poles at odd multiples of pi/2 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments tan has poles at odd multiples of pi/2 undefined where tan(x + 2)**2 + 1 = 0 undefined where tan(x + 2) = 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 undefined where tan(x + 2)**2 + 1 = 0 undefined where tan(x + 2) = 0 |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 undefined where tan(x + 2)**2 + 1 = 0 undefined where tan(x + 2) = 0 |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 undefined where tan(x + 2)**2 + 1 = 0 undefined where tan(x + 2) = 0 |
| 8 | ≈ Checked numerically | sympy 1.14.0 | sympy 1.14.0: simplify left (5*tan(x + 2)**2 - 5*sec(x + 2)**2 + 5)/(tan(x + 2)**3 + tan(x + 2)); numeric agreement only, at 24 of 24 sampled points tan has poles at odd multiples of pi/2 undefined where tan(x + 2)**2 + 1 = 0 undefined where tan(x + 2) = 0 sec has poles at odd multiples of pi/2 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(x + 2)**2 + 1 = 0 undefined where tan(x + 2) = 0 |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(x + 2)**2 + 1 = 0 undefined where tan(x + 2) = 0 |
| 11 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(x + 2)**2 + 1 = 0 undefined where tan(x + 2) = 0 |
| 12 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(x + 2)**2 + 1 = 0 undefined where tan(x + 2) = 0 |
| 13 | ≈ Checked numerically | sympy 1.14.0 | sympy 1.14.0: simplify left (-5*tan(x + 2)**2 + 5*sec(x + 2)**2 - 5)/(tan(x + 2)**3 + tan(x + 2)); numeric agreement only, at 24 of 24 sampled points tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(x + 2)**2 + 1 = 0 undefined where tan(x + 2) = 0 |
| 14 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 undefined where tan(x + 2) = 0 |
| 15 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 undefined where tan(x + 2) = 0 cot has poles at multiples of pi |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 undefined where tan(x + 2) = 0 |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass
Every verdict on record (4)
qwen3.6:27b-mlx: pass 2026-10-03gpt-oss:20b: pass 2026-10-03qwen3.6:27b-mlx: pass 2026-10-03 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The algebraic simplifications and trigonometric identities are applied correctly.gpt-oss:20b: pass 2026-10-03
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-10-03 with SymPy 1.14.0.