∫Calc Practice

Derivative of \( \displaystyle - \frac{5 \ln{\left(\tan^{2}{\left(x + 2 \right)} + 1 \right)}}{2} + 5 \ln{\left(\tan{\left(x + 2 \right)} \right)} \)

Problem 2.1449 · hard Beautiful

Differentiate \( \displaystyle f(x) = - \frac{5 \ln{\left(\tan^{2}{\left(x + 2 \right)} + 1 \right)}}{2} + 5 \ln{\left(\tan{\left(x + 2 \right)} \right)} \).
  1. \[ \frac{d}{d x} \left(- \frac{5 \ln{\left(\tan^{2}{\left(x + 2 \right)} + 1 \right)}}{2} + 5 \ln{\left(\tan{\left(x + 2 \right)} \right)}\right) \]
    derivativeStart with the derivative of the function.✓ Proved
  2. \[ = \frac{d}{d x} \left(- \frac{5 \ln{\left(\tan^{2}{\left(x + 2 \right)} + 1 \right)}}{2}\right) + \frac{d}{d x} 5 \ln{\left(\tan{\left(x + 2 \right)} \right)} \]
    sumApply the sum rule.✓ Proved
  3. \[ = \frac{d}{d x} \left(- \frac{5 \ln{\left(\tan^{2}{\left(x + 2 \right)} + 1 \right)}}{2}\right) + 5 \frac{d}{d x} \ln{\left(\tan{\left(x + 2 \right)} \right)} \]
    constant-multipleFactor out the constant from the second term.✓ Proved
  4. \[ = \frac{5 \frac{d}{d x} \tan{\left(x + 2 \right)}}{\tan{\left(x + 2 \right)}} - \frac{5 \frac{d}{d x} \left(\tan^{2}{\left(x + 2 \right)} + 1\right)}{2 \left(\tan^{2}{\left(x + 2 \right)} + 1\right)} \]
    logarithmicApply the chain rule for the logarithm.✓ Proved
  5. \[ = \frac{5 \frac{d}{d x} \tan{\left(x + 2 \right)}}{\tan{\left(x + 2 \right)}} - \frac{5 \left(\frac{d}{d x} 1 + \frac{d}{d x} \tan^{2}{\left(x + 2 \right)}\right)}{2 \left(\tan^{2}{\left(x + 2 \right)} + 1\right)} \]
    sumApply the sum rule to the inner derivative.✓ Proved
  6. \[ = \frac{5 \frac{d}{d x} \tan{\left(x + 2 \right)}}{\tan{\left(x + 2 \right)}} - \frac{5 \frac{d}{d x} \tan^{2}{\left(x + 2 \right)}}{2 \left(\tan^{2}{\left(x + 2 \right)} + 1\right)} \]
    constantThe derivative of a constant is zero.✓ Proved
  7. \[ = \frac{5 \frac{d}{d x} \tan{\left(x + 2 \right)}}{\tan{\left(x + 2 \right)}} - \frac{5 \tan{\left(x + 2 \right)} \frac{d}{d x} \tan{\left(x + 2 \right)}}{\tan^{2}{\left(x + 2 \right)} + 1} \]
    powerApply the power rule to the squared term.✓ Proved
  8. \[ = \frac{5 \sec^{2}{\left(x + 2 \right)}}{\tan{\left(x + 2 \right)}} - \frac{5 \tan{\left(x + 2 \right)} \sec^{2}{\left(x + 2 \right)}}{\tan^{2}{\left(x + 2 \right)} + 1} \]
    trig algebraSubstitute the derivative of tan(x+2). Simplify the coefficients.≈ Checked numerically
  9. \[ = \frac{5 \left(\tan^{2}{\left(x + 2 \right)} + 1\right) \sec^{2}{\left(x + 2 \right)} - 5 \tan^{2}{\left(x + 2 \right)} \sec^{2}{\left(x + 2 \right)}}{\left(\tan^{2}{\left(x + 2 \right)} + 1\right) \tan{\left(x + 2 \right)}} \]
    algebraFind a common denominator.✓ Proved
  10. \[ = \frac{5 \sec^{2}{\left(x + 2 \right)}}{\left(\tan^{2}{\left(x + 2 \right)} + 1\right) \tan{\left(x + 2 \right)}} \]
    algebra simplifyDistribute the numerator. Cancel the common terms in the numerator.✓ Proved
  11. \[ = \frac{5}{\tan{\left(x + 2 \right)}} \]
    algebra simplifyUse the identity 1 + tan(x)^2 = sec(x)^2. Cancel the sec(x+2)^2 term.≈ Checked numerically
  12. \[ = 5 \cot{\left(x + 2 \right)} \]
    trigUse the identity 1/tan(x) = cot(x).✓ Proved
Answer \( \frac{5}{\tan{\left(x + 2 \right)}} \)
Mind the domain. The answer is also defined at points where f(x) is not. Substituting there gives a number that is not a slope of f.

✓ Nihil obstat Lines: 14 proved, 2 checked numerically. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
tan has poles at odd multiples of pi/2
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
tan has poles at odd multiples of pi/2
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
tan has poles at odd multiples of pi/2
undefined where tan(x + 2)**2 + 1 = 0
undefined where tan(x + 2) = 0
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
undefined where tan(x + 2)**2 + 1 = 0
undefined where tan(x + 2) = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
undefined where tan(x + 2)**2 + 1 = 0
undefined where tan(x + 2) = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
undefined where tan(x + 2)**2 + 1 = 0
undefined where tan(x + 2) = 0
8≈ Checked numericallysympy 1.14.0sympy 1.14.0: simplify left (5*tan(x + 2)**2 - 5*sec(x + 2)**2 + 5)/(tan(x + 2)**3 + tan(x + 2)); numeric agreement only, at 24 of 24 sampled points
tan has poles at odd multiples of pi/2
undefined where tan(x + 2)**2 + 1 = 0
undefined where tan(x + 2) = 0
sec has poles at odd multiples of pi/2
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
sec has poles at odd multiples of pi/2
undefined where tan(x + 2)**2 + 1 = 0
undefined where tan(x + 2) = 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
sec has poles at odd multiples of pi/2
undefined where tan(x + 2)**2 + 1 = 0
undefined where tan(x + 2) = 0
11✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
sec has poles at odd multiples of pi/2
undefined where tan(x + 2)**2 + 1 = 0
undefined where tan(x + 2) = 0
12✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
sec has poles at odd multiples of pi/2
undefined where tan(x + 2)**2 + 1 = 0
undefined where tan(x + 2) = 0
13≈ Checked numericallysympy 1.14.0sympy 1.14.0: simplify left (-5*tan(x + 2)**2 + 5*sec(x + 2)**2 - 5)/(tan(x + 2)**3 + tan(x + 2)); numeric agreement only, at 24 of 24 sampled points
tan has poles at odd multiples of pi/2
sec has poles at odd multiples of pi/2
undefined where tan(x + 2)**2 + 1 = 0
undefined where tan(x + 2) = 0
14✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
undefined where tan(x + 2) = 0
15✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
undefined where tan(x + 2) = 0
cot has poles at multiples of pi
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
undefined where tan(x + 2) = 0
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-03
  • gpt-oss:20b: pass 2026-10-03
  • qwen3.6:27b-mlx: pass 2026-10-03 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The algebraic simplifications and trigonometric identities are applied correctly.
  • gpt-oss:20b: pass 2026-10-03

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-10-03 with SymPy 1.14.0.