Derivative of \( \displaystyle \frac{\ln{\left(\tan^{2}{\left(5 x + 2 \right)} + 1 \right)}}{10} - \frac{\ln{\left(\tan{\left(5 x + 2 \right)} \right)}}{5} \)
Problem 2.1384 · hard
Differentiate \( \displaystyle f(x) = \frac{\ln{\left(\tan^{2}{\left(5 x + 2 \right)} + 1 \right)}}{10} - \frac{\ln{\left(\tan{\left(5 x + 2 \right)} \right)}}{5} \).
- \[ \frac{d}{d x} \left(\frac{\ln{\left(\tan^{2}{\left(5 x + 2 \right)} + 1 \right)}}{10} - \frac{\ln{\left(\tan{\left(5 x + 2 \right)} \right)}}{5}\right) \]derivativeStart with the derivative of the function.✓ Proved
- \[ = \frac{d}{d x} \frac{\ln{\left(\tan^{2}{\left(5 x + 2 \right)} + 1 \right)}}{10} - \frac{d}{d x} \frac{\ln{\left(\tan{\left(5 x + 2 \right)} \right)}}{5} \]sumApply the sum rule.✓ Proved
- \[ = \frac{\frac{d}{d x} \ln{\left(\tan^{2}{\left(5 x + 2 \right)} + 1 \right)}}{10} - \frac{\frac{d}{d x} \ln{\left(\tan{\left(5 x + 2 \right)} \right)}}{5} \]constant-multiplePull out the constant factors.✓ Proved
- \[ = - \frac{\frac{d}{d x} \tan{\left(5 x + 2 \right)}}{5 \tan{\left(5 x + 2 \right)}} + \frac{\frac{d}{d x} \left(\tan^{2}{\left(5 x + 2 \right)} + 1\right)}{10 \left(\tan^{2}{\left(5 x + 2 \right)} + 1\right)} \]chainApply the chain rule to both terms.✓ Proved
- \[ = - \frac{\frac{d}{d x} \tan{\left(5 x + 2 \right)}}{5 \tan{\left(5 x + 2 \right)}} + \frac{\frac{d}{d x} 1 + \frac{d}{d x} \tan^{2}{\left(5 x + 2 \right)}}{10 \left(\tan^{2}{\left(5 x + 2 \right)} + 1\right)} \]sumApply the sum rule inside the first derivative.✓ Proved
- \[ = - \frac{\frac{d}{d x} \tan{\left(5 x + 2 \right)}}{5 \tan{\left(5 x + 2 \right)}} + \frac{\tan{\left(5 x + 2 \right)} \frac{d}{d x} \tan{\left(5 x + 2 \right)}}{5 \left(\tan^{2}{\left(5 x + 2 \right)} + 1\right)} \]powerApply the power rule.✓ Proved
- \[ = - \frac{\sec^{2}{\left(5 x + 2 \right)}}{\tan{\left(5 x + 2 \right)}} + \frac{\tan{\left(5 x + 2 \right)} \sec^{2}{\left(5 x + 2 \right)}}{\tan^{2}{\left(5 x + 2 \right)} + 1} \]chain algebra algebraApply the chain rule to the tangent function. Simplify the coefficients. Simplify the fractions.≈ Checked numerically
- \[ = \left(- \frac{1}{\tan{\left(5 x + 2 \right)}} + \frac{\tan{\left(5 x + 2 \right)}}{\tan^{2}{\left(5 x + 2 \right)} + 1}\right) \sec^{2}{\left(5 x + 2 \right)} \]algebraFactor out the common secant term.✓ Proved
- \[ = - \frac{\sec^{2}{\left(5 x + 2 \right)}}{\left(\tan^{2}{\left(5 x + 2 \right)} + 1\right) \tan{\left(5 x + 2 \right)}} \]algebra algebra algebra algebraFind a common denominator inside the parentheses. Distribute the numerator. Combine like terms in the numerator. Simplify the expression.✓ Proved
- \[ = - \frac{1}{\tan{\left(5 x + 2 \right)}} \]algebra algebraUse the identity tan(u)**2 + 1 = sec(u)**2. Cancel the secant squared term.≈ Checked numerically
- \[ = - \cot{\left(5 x + 2 \right)} \]simplifyUse the definition of cotangent.✓ Proved
Answer \( - \frac{1}{\tan{\left(5 x + 2 \right)}} \)
Mind the domain. The answer is also defined at points where f(x) is not. Substituting there gives a number that is not a slope of f.
Lines: 16 proved, 2 checked numerically. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments tan has poles at odd multiples of pi/2 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments tan has poles at odd multiples of pi/2 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments tan has poles at odd multiples of pi/2 undefined where tan(5*x + 2) = 0 undefined where tan(5*x + 2)**2 + 1 = 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 undefined where tan(5*x + 2) = 0 undefined where tan(5*x + 2)**2 + 1 = 0 |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 undefined where tan(5*x + 2) = 0 undefined where tan(5*x + 2)**2 + 1 = 0 |
| 7 | ≈ Checked numerically | sympy 1.14.0 | sympy 1.14.0: simplify left (-tan(5*x + 2)**2 + sec(5*x + 2)**2 - 1)/(tan(5*x + 2)**3 + tan(5*x + 2)); numeric agreement only, at 24 of 24 sampled points tan has poles at odd multiples of pi/2 undefined where tan(5*x + 2) = 0 undefined where tan(5*x + 2)**2 + 1 = 0 sec has poles at odd multiples of pi/2 |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(5*x + 2)**2 + 1 = 0 undefined where tan(5*x + 2) = 0 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(5*x + 2)**2 + 1 = 0 undefined where tan(5*x + 2) = 0 |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(5*x + 2)**2 + 1 = 0 undefined where tan(5*x + 2) = 0 |
| 11 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(5*x + 2)**2 + 1 = 0 undefined where tan(5*x + 2) = 0 |
| 12 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(5*x + 2) = 0 undefined where tan(5*x + 2)**2 + 1 = 0 |
| 13 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(5*x + 2) = 0 undefined where tan(5*x + 2)**2 + 1 = 0 |
| 14 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(5*x + 2) = 0 undefined where tan(5*x + 2)**2 + 1 = 0 |
| 15 | ≈ Checked numerically | sympy 1.14.0 | sympy 1.14.0: simplify left (tan(5*x + 2)**2 - sec(5*x + 2)**2 + 1)/(tan(5*x + 2)**3 + tan(5*x + 2)); numeric agreement only, at 24 of 24 sampled points tan has poles at odd multiples of pi/2 sec has poles at odd multiples of pi/2 undefined where tan(5*x + 2) = 0 undefined where tan(5*x + 2)**2 + 1 = 0 |
| 16 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 undefined where tan(5*x + 2) = 0 |
| 17 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 undefined where tan(5*x + 2) = 0 cot has poles at multiples of pi |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 tan has poles at odd multiples of pi/2 undefined where tan(5*x + 2) = 0 |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: fail (error) — Step 4 applies the chain rule to both terms simultaneously, violating the contract that each step must change only one thing. Additionally, Step 7 applies the chain rule to the inner function of the tangent derivative in both terms at once, which is another multi-rule application defect.
Every verdict on record (4)
qwen3.6:27b-mlx: fail (error) 2026-10-03 — Step 4 applies the chain rule to both terms simultaneously, violating the contract that each step must change only one thing. Additionally, Step 7 applies the chain rule to the inner function of the tangent derivative in both terms at once, which is another multi-rule application defect.gpt-oss:20b: pass 2026-10-03qwen3.6:27b-mlx: pass 2026-10-03 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The labels used are appropriate for the operations performed, and the final simplification is correct.gpt-oss:20b: inconclusive 2026-10-03 — reviewer response could not be parsed: {"verdict":"fail","severity":"style","notes":"Step 5 incorrectly labels the application of the derivative of a sum as a \"sum\" rule. The derivative of \(tan(5x+2)^2+1\) is a single application of the
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-10-03 with SymPy 1.14.0.