∫Calc Practice
Home›Calculus 1›Chain rule›Problem 2.1260

Derivative of \( \displaystyle \ln{\left(\frac{x}{\sqrt{x^{2} + 1}} \right)} \)

Problem 2.1260 · hard Beautiful

Differentiate \( \displaystyle f(x) = \ln{\left(\frac{x}{\sqrt{x^{2} + 1}} \right)} \).
  1. \[ \frac{d}{d x} \ln{\left(\frac{x}{\sqrt{x^{2} + 1}} \right)} \]
    derivativeStart with the derivative of the function.✓ Proved
  2. \[ = \frac{d}{d x} \left(\ln{\left(x \right)} - \ln{\left(\sqrt{x^{2} + 1} \right)}\right) \]
    algebra algebraUse logarithm properties to split the fraction. Rewrite the square root as a fractional power.✓ Proved
  3. \[ = \frac{d}{d x} \ln{\left(x \right)} - \frac{d}{d x} \ln{\left(\sqrt{x^{2} + 1} \right)} \]
    sumApply the difference rule for derivatives.✓ Proved
  4. \[ = \frac{d}{d x} \ln{\left(x \right)} - \frac{d}{d x} \frac{\ln{\left(x^{2} + 1 \right)}}{2} \]
    constant-multiplePull out the constant factor 1/2 using the power rule for logs.✓ Proved
  5. \[ = \frac{d}{d x} \ln{\left(x \right)} - \frac{\frac{d}{d x} \ln{\left(x^{2} + 1 \right)}}{2} \]
    constant-multipleApply the constant multiple rule.✓ Proved
  6. \[ = - \frac{\frac{d}{d x} \ln{\left(x^{2} + 1 \right)}}{2} + \frac{1}{x} \]
    derivativeDifferentiate the first term.✓ Proved
  7. \[ = - \frac{\frac{d}{d x} \left(x^{2} + 1\right)}{2 \left(x^{2} + 1\right)} + \frac{1}{x} \]
    chainApply the chain rule to the second term.✓ Proved
  8. \[ = - \frac{x}{x^{2} + 1} + \frac{1}{x} \]
    derivative algebraDifferentiate the inner function x**2 + 1. Simplify the expression by canceling the 2 and the 1/2.✓ Proved
  9. \[ = \frac{1}{x \left(x^{2} + 1\right)} \]
    algebra simplifyFind a common denominator to combine the terms. Simplify the numerator.✓ Proved
Answer \( \frac{1}{x^{3} + x} \)
Mind the domain. The answer is also defined on (-oo, 0), where f(x) is not. Substituting there gives a number that is not a slope of f.

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x**2 + 1 = 0
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x = 0
undefined where x**2 + 1 = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 + 1 = 0
undefined where x = 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 + 1 = 0
undefined where x = 0
11✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 + 1 = 0
undefined where x = 0
12✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 + 1 = 0
undefined where x = 0
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
undefined where x**3 + x = 0
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies logarithmic properties, the chain rule, and algebraic simplification. Each step isolates a single rule application as required.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-09-29 — The solution correctly applies logarithmic properties, the chain rule, and algebraic simplification. Each step isolates a single rule application as required.
  • gpt-oss:20b: pass 2026-09-29
  • qwen3.6:27b-mlx: pass 2026-09-29
  • gpt-oss:20b: pass 2026-09-29

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-09-29 with SymPy 1.14.0.