Derivative of \( \displaystyle \ln{\left(\frac{x}{\sqrt{x^{2} + 1}} \right)} \)
Problem 2.1260 · hard Beautiful
Differentiate \( \displaystyle f(x) = \ln{\left(\frac{x}{\sqrt{x^{2} + 1}} \right)} \).
- \[ \frac{d}{d x} \ln{\left(\frac{x}{\sqrt{x^{2} + 1}} \right)} \]derivativeStart with the derivative of the function.✓ Proved
- \[ = \frac{d}{d x} \left(\ln{\left(x \right)} - \ln{\left(\sqrt{x^{2} + 1} \right)}\right) \]algebra algebraUse logarithm properties to split the fraction. Rewrite the square root as a fractional power.✓ Proved
- \[ = \frac{d}{d x} \ln{\left(x \right)} - \frac{d}{d x} \ln{\left(\sqrt{x^{2} + 1} \right)} \]sumApply the difference rule for derivatives.✓ Proved
- \[ = \frac{d}{d x} \ln{\left(x \right)} - \frac{d}{d x} \frac{\ln{\left(x^{2} + 1 \right)}}{2} \]constant-multiplePull out the constant factor 1/2 using the power rule for logs.✓ Proved
- \[ = \frac{d}{d x} \ln{\left(x \right)} - \frac{\frac{d}{d x} \ln{\left(x^{2} + 1 \right)}}{2} \]constant-multipleApply the constant multiple rule.✓ Proved
- \[ = - \frac{\frac{d}{d x} \ln{\left(x^{2} + 1 \right)}}{2} + \frac{1}{x} \]derivativeDifferentiate the first term.✓ Proved
- \[ = - \frac{\frac{d}{d x} \left(x^{2} + 1\right)}{2 \left(x^{2} + 1\right)} + \frac{1}{x} \]chainApply the chain rule to the second term.✓ Proved
- \[ = - \frac{x}{x^{2} + 1} + \frac{1}{x} \]derivative algebraDifferentiate the inner function x**2 + 1. Simplify the expression by canceling the 2 and the 1/2.✓ Proved
- \[ = \frac{1}{x \left(x^{2} + 1\right)} \]algebra simplifyFind a common denominator to combine the terms. Simplify the numerator.✓ Proved
Answer \( \frac{1}{x^{3} + x} \)
Mind the domain. The answer is also defined on (-oo, 0), where f(x) is not. Substituting there gives a number that is not a slope of f.
✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where x**2 + 1 = 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where x = 0 |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where x = 0 undefined where x**2 + 1 = 0 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 undefined where x = 0 |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 undefined where x = 0 |
| 11 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 undefined where x = 0 |
| 12 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x**2 + 1 = 0 undefined where x = 0 |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 undefined where x**3 + x = 0 |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly applies logarithmic properties, the chain rule, and algebraic simplification. Each step isolates a single rule application as required.
Every verdict on record (4)
qwen3.6:27b-mlx: pass 2026-09-29 — The solution correctly applies logarithmic properties, the chain rule, and algebraic simplification. Each step isolates a single rule application as required.gpt-oss:20b: pass 2026-09-29qwen3.6:27b-mlx: pass 2026-09-29gpt-oss:20b: pass 2026-09-29
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-09-29 with SymPy 1.14.0.