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Derivative of \( \displaystyle - x^{2} + 2 x \left(x + 1\right) \ln{\left(2 x + 1 \right)} - x + \frac{\ln{\left(2 x + 1 \right)}}{2} \)

Problem 2.1208 · hard

Differentiate \( \displaystyle f(x) = - x^{2} + 2 x \left(x + 1\right) \ln{\left(2 x + 1 \right)} - x + \frac{\ln{\left(2 x + 1 \right)}}{2} \).
  1. \[ \frac{d}{d x} \left(- x^{2} + 2 x \left(x + 1\right) \ln{\left(2 x + 1 \right)} - x + \frac{\ln{\left(2 x + 1 \right)}}{2}\right) \]
    derivativeStart with the derivative of the function.✓ Proved
  2. \[ = \frac{d}{d x} \left(- x\right) + \frac{d}{d x} \left(- x^{2}\right) + \frac{d}{d x} 2 x \left(x + 1\right) \ln{\left(2 x + 1 \right)} + \frac{d}{d x} \frac{\ln{\left(2 x + 1 \right)}}{2} \]
    sum constant-multipleApply the sum rule. Factor out the constant 1/2.✓ Proved
  3. \[ = \frac{d}{d x} \left(- x\right) + \frac{d}{d x} \left(- x^{2}\right) + \frac{d}{d x} 2 x \left(x + 1\right) \ln{\left(2 x + 1 \right)} + \frac{\frac{d}{d x} \ln{\left(2 x + 1 \right)}}{2} \]
    constantMove the constant outside the derivative.✓ Proved
  4. \[ = \frac{d}{d x} \left(- x\right) + \frac{d}{d x} \left(- x^{2}\right) + \frac{d}{d x} 2 x \left(x + 1\right) \ln{\left(2 x + 1 \right)} + \frac{\frac{d}{d x} \left(2 x + 1\right)}{2 \left(2 x + 1\right)} \]
    chainApply the chain rule to the logarithm.✓ Proved
  5. \[ = \frac{d}{d x} \left(- x\right) + \frac{d}{d x} \left(- x^{2}\right) + \frac{d}{d x} 2 x \left(x + 1\right) \ln{\left(2 x + 1 \right)} + \frac{1}{2 x + 1} \]
    derivative algebraDifferentiate the inner function 2x + 1. Simplify the constant term.✓ Proved
  6. \[ = 2 x \left(x + 1\right) \frac{d}{d x} \ln{\left(2 x + 1 \right)} + \ln{\left(2 x + 1 \right)} \frac{d}{d x} 2 x \left(x + 1\right) + \frac{d}{d x} \left(- x\right) + \frac{d}{d x} \left(- x^{2}\right) + \frac{1}{2 x + 1} \]
    productApply the product rule to the second term.✓ Proved
  7. \[ = 2 x \left(x + 1\right) \frac{d}{d x} \ln{\left(2 x + 1 \right)} + \ln{\left(2 x + 1 \right)} \frac{d}{d x} \left(2 x^{2} + 2 x\right) + \frac{d}{d x} \left(- x\right) + \frac{d}{d x} \left(- x^{2}\right) + \frac{1}{2 x + 1} \]
    algebraExpand the polynomial inside the derivative.✓ Proved
  8. \[ = \frac{2 x \left(x + 1\right) \frac{d}{d x} \left(2 x + 1\right)}{2 x + 1} + \ln{\left(2 x + 1 \right)} \frac{d}{d x} \left(2 x^{2} + 2 x\right) + \frac{d}{d x} \left(- x\right) + \frac{d}{d x} \left(- x^{2}\right) + \frac{1}{2 x + 1} \]
    chainApply the chain rule to the logarithm term again.✓ Proved
  9. \[ = \frac{4 x \left(x + 1\right)}{2 x + 1} + \ln{\left(2 x + 1 \right)} \frac{d}{d x} \left(2 x^{2} + 2 x\right) + \frac{d}{d x} \left(- x\right) + \frac{d}{d x} \left(- x^{2}\right) + \frac{1}{2 x + 1} \]
    derivative algebraDifferentiate the inner function 2x + 1. Simplify the product of constants and variables.✓ Proved
  10. \[ = \frac{4 x \left(x + 1\right)}{2 x + 1} - 2 x + \ln{\left(2 x + 1 \right)} \frac{d}{d x} \left(2 x^{2} + 2 x\right) - 1 + \frac{1}{2 x + 1} \]
    derivativeDifferentiate the remaining polynomial terms.✓ Proved
  11. \[ = \frac{4 x \left(x + 1\right)}{2 x + 1} - 2 x + \left(4 x + 2\right) \ln{\left(2 x + 1 \right)} - 1 + \frac{1}{2 x + 1} \]
    derivativeDifferentiate the polynomial 2x^2 + 2x.✓ Proved
  12. \[ = - 2 x + \left(4 x + 2\right) \ln{\left(2 x + 1 \right)} - 1 + \frac{4 x^{2} + 4 x + 1}{2 x + 1} \]
    algebraCombine the fractions with the same denominator.✓ Proved
  13. \[ = \left(4 x + 2\right) \ln{\left(2 x + 1 \right)} \]
    algebra simplify simplifyRecognize the numerator as a perfect square. Simplify the expression by canceling terms. Final simplified result.✓ Proved
Answer \( 2 \left(2 x + 1\right) \ln{\left(2 x + 1 \right)} \)

Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
11✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
12✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
13✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
14✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
15✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
16✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
17✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
18✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: fail (error) — Step 17 incorrectly drops the constant –1 from the expression, leading to an incorrect final result. The simplification should cancel –2*x with +2*x and –1 with +1, yielding (4*x+2)*log(2*x+1), but the omitted –1 makes the step algebraically wrong.
  • qwen3.6:27b-mlx: pass — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. All labels are appropriate for the operations performed.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-09-29 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. All labels are appropriate for the operations performed.
  • gpt-oss:20b: fail (error) 2026-09-29 — Step 17 incorrectly drops the constant –1 from the expression, leading to an incorrect final result. The simplification should cancel –2*x with +2*x and –1 with +1, yielding (4*x+2)*log(2*x+1), but the omitted –1 makes the step algebraically wrong.
  • qwen3.6:27b-mlx: pass 2026-09-29
  • gpt-oss:20b: pass 2026-09-29

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-09-29 with SymPy 1.14.0.