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Derivative of \( \displaystyle - \frac{\ln{\left(\tan^{2}{\left(2 x - 1 \right)} + 1 \right)}}{4} + \frac{\ln{\left(\tan{\left(2 x - 1 \right)} \right)}}{2} \)

Problem 2.112 · hard

Differentiate \( \displaystyle f(x) = - \frac{\ln{\left(\tan^{2}{\left(2 x - 1 \right)} + 1 \right)}}{4} + \frac{\ln{\left(\tan{\left(2 x - 1 \right)} \right)}}{2} \).
  1. \[ \frac{d}{d x} \left(- \frac{\ln{\left(\tan^{2}{\left(2 x - 1 \right)} + 1 \right)}}{4} + \frac{\ln{\left(\tan{\left(2 x - 1 \right)} \right)}}{2}\right) \]
    derivative constant-multipleStart with the derivative of the function. Distribute the constant factors.✓ Proved
  2. \[ = \frac{d}{d x} \left(- \frac{\ln{\left(\tan^{2}{\left(2 x - 1 \right)} + 1 \right)}}{4}\right) + \frac{d}{d x} \frac{\ln{\left(\tan{\left(2 x - 1 \right)} \right)}}{2} \]
    sumApply the sum rule for derivatives.✓ Proved
  3. \[ = \frac{d}{d x} \left(- \frac{\ln{\left(\tan^{2}{\left(2 x - 1 \right)} + 1 \right)}}{4}\right) + \frac{\frac{d}{d x} \ln{\left(\tan{\left(2 x - 1 \right)} \right)}}{2} \]
    constant-multipleFactor out the constant from the second term.✓ Proved
  4. \[ = \frac{\frac{d}{d x} \tan{\left(2 x - 1 \right)}}{2 \tan{\left(2 x - 1 \right)}} - \frac{\frac{d}{d x} \left(\tan^{2}{\left(2 x - 1 \right)} + 1\right)}{4 \left(\tan^{2}{\left(2 x - 1 \right)} + 1\right)} \]
    chainApply the chain rule to both logarithmic terms.✓ Proved
  5. \[ = \frac{\frac{d}{d x} \tan{\left(2 x - 1 \right)}}{2 \tan{\left(2 x - 1 \right)}} - \frac{\frac{d}{d x} 1 + \frac{d}{d x} \tan^{2}{\left(2 x - 1 \right)}}{4 \left(\tan^{2}{\left(2 x - 1 \right)} + 1\right)} \]
    sumApply the sum rule to the inner derivative.✓ Proved
  6. \[ = \frac{\frac{d}{d x} \tan{\left(2 x - 1 \right)}}{2 \tan{\left(2 x - 1 \right)}} - \frac{\tan{\left(2 x - 1 \right)} \frac{d}{d x} \tan{\left(2 x - 1 \right)}}{2 \left(\tan^{2}{\left(2 x - 1 \right)} + 1\right)} \]
    powerApply the power rule to the squared tangent term.✓ Proved
  7. \[ = \frac{\sec^{2}{\left(2 x - 1 \right)}}{\tan{\left(2 x - 1 \right)}} - \frac{\tan{\left(2 x - 1 \right)} \sec^{2}{\left(2 x - 1 \right)}}{\tan^{2}{\left(2 x - 1 \right)} + 1} \]
    chain algebra algebraApply the chain rule to the derivative of tan(2*x - 1). Simplify the products in the numerators. Simplify the fractions by combining constants.≈ Checked numerically
  8. \[ = - \tan{\left(2 x - 1 \right)} + \frac{\sec^{2}{\left(2 x - 1 \right)}}{\tan{\left(2 x - 1 \right)}} \]
    rewrite simplifyUse the identity tan(u)**2 + 1 = sec(u)**2. Cancel the sec(2*x - 1)**2 term in the first fraction.≈ Checked numerically
  9. \[ = \frac{\tan^{2}{\left(2 x - 1 \right)} + 1}{\tan{\left(2 x - 1 \right)}} - \tan{\left(2 x - 1 \right)} \]
    rewriteRewrite sec(2*x - 1)**2 in terms of tangent.≈ Checked numerically
  10. \[ = \frac{1}{\tan{\left(2 x - 1 \right)}} \]
    algebra simplifySplit the fraction into two parts. Combine the tangent terms.✓ Proved
  11. \[ = \cot{\left(2 x - 1 \right)} \]
    simplifyUse the definition of the cotangent function.✓ Proved
Answer \( \frac{1}{\tan{\left(2 x - 1 \right)}} \)
Mind the domain. The answer is also defined at points where f(x) is not. Substituting there gives a number that is not a slope of f.

Lines: 14 proved, 3 checked numerically. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
tan has poles at odd multiples of pi/2
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
tan has poles at odd multiples of pi/2
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
tan has poles at odd multiples of pi/2
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
tan has poles at odd multiples of pi/2
undefined where tan(2*x - 1)**2 + 1 = 0
undefined where tan(2*x - 1) = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
undefined where tan(2*x - 1)**2 + 1 = 0
undefined where tan(2*x - 1) = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
undefined where tan(2*x - 1)**2 + 1 = 0
undefined where tan(2*x - 1) = 0
8≈ Checked numericallysympy 1.14.0sympy 1.14.0: simplify left (tan(2*x - 1)**2 - sec(2*x - 1)**2 + 1)/(tan(2*x - 1)**3 + tan(2*x - 1)); numeric agreement only, at 24 of 24 sampled points
tan has poles at odd multiples of pi/2
undefined where tan(2*x - 1)**2 + 1 = 0
undefined where tan(2*x - 1) = 0
sec has poles at odd multiples of pi/2
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
sec has poles at odd multiples of pi/2
undefined where tan(2*x - 1)**2 + 1 = 0
undefined where tan(2*x - 1) = 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
sec has poles at odd multiples of pi/2
undefined where tan(2*x - 1)**2 + 1 = 0
undefined where tan(2*x - 1) = 0
11≈ Checked numericallysympy 1.14.0sympy 1.14.0: simplify left (tan(2*x - 1)**2 - sec(2*x - 1)**2 + 1)*tan(2*x - 1)/(tan(2*x - 1)**2 + 1); numeric agreement only, at 24 of 24 sampled points
tan has poles at odd multiples of pi/2
sec has poles at odd multiples of pi/2
undefined where tan(2*x - 1)**2 + 1 = 0
undefined where tan(2*x - 1) = 0
12✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
sec has poles at odd multiples of pi/2
undefined where tan(2*x - 1) = 0
13≈ Checked numericallysympy 1.14.0sympy 1.14.0: simplify left (-tan(2*x - 1)**2 + sec(2*x - 1)**2 - 1)/tan(2*x - 1); numeric agreement only, at 24 of 24 sampled points
tan has poles at odd multiples of pi/2
sec has poles at odd multiples of pi/2
undefined where tan(2*x - 1) = 0
14✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
undefined where tan(2*x - 1) = 0
15✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
undefined where tan(2*x - 1) = 0
16✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
undefined where tan(2*x - 1) = 0
cot has poles at multiples of pi
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
undefined where tan(2*x - 1) = 0
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: fail (error) — Step 5 applies the chain rule to two logarithmic terms in a single step, violating the rule that each step must change only one thing. This is a multi‑rule application and should be split into two separate steps.
  • deepseek-r1:70b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies differentiation rules and algebraic simplifications. Each step adheres to the single-change constraint and uses valid labels from the fixed vocabulary.
Every verdict on record (15)
  • qwen3.6:27b-mlx: pass 2026-09-20 — The solution correctly applies differentiation rules and algebraic simplifications. Each step adheres to the single-change constraint and uses valid labels from the fixed vocabulary.
  • gpt-oss:20b: fail (error) 2026-09-20 — Step 5 applies the chain rule to two logarithmic terms in a single step, violating the rule that each step must change only one thing. This is a multi‑rule application and should be split into two separate steps.
  • qwen3.6:27b-mlx: pass 2026-09-20 — The solution correctly applies differentiation rules and algebraic simplifications. Each step adheres to the single-change constraint and uses valid labels from the fixed vocabulary.
  • gpt-oss:20b: pass 2026-09-20
  • qwen3.6:27b-mlx: pass 2026-09-19 — The solution correctly applies differentiation rules and algebraic simplifications. Each step adheres to the single-change constraint and uses valid labels from the fixed vocabulary.
  • deepseek-r1:70b: pass 2026-09-19
  • gpt-oss:20b: pass 2026-09-19
  • qwen3.6:27b-mlx: pass 2026-09-19 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The algebraic simplifications and trigonometric identities are applied correctly to reach the final result.
  • deepseek-r1:70b: pass 2026-09-19
  • gpt-oss:20b: pass 2026-09-19
  • qwen3.6:27b-mlx: pass 2026-09-18 — The solution correctly applies differentiation rules and algebraic simplifications. Each step isolates a single transformation, and the labels accurately reflect the operations performed.
  • deepseek-r1:70b: pass 2026-09-18
  • gpt-oss:20b: pass 2026-09-18
  • gpt-oss:20b: inconclusive 2026-09-17 — reviewer response could not be parsed:
  • deepseek-r1:70b: pass 2026-09-17

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-09-26 with SymPy 1.14.0.