∫Calc Practice

Derivative of \( \displaystyle 3 x \ln{\left(5 x - 1 \right)} - 3 x - \frac{3 \ln{\left(5 x - 1 \right)}}{5} \)

Problem 2.1102 · hard

Differentiate \( \displaystyle f(x) = 3 x \ln{\left(5 x - 1 \right)} - 3 x - \frac{3 \ln{\left(5 x - 1 \right)}}{5} \).
  1. \[ \frac{d}{d x} \left(3 x \ln{\left(5 x - 1 \right)} - 3 x - \frac{3 \ln{\left(5 x - 1 \right)}}{5}\right) \]
    derivativeStart with the derivative of the function.✓ Proved
  2. \[ = - \frac{d}{d x} 3 x + \frac{d}{d x} 3 x \ln{\left(5 x - 1 \right)} - \frac{d}{d x} \frac{3 \ln{\left(5 x - 1 \right)}}{5} \]
    sumApply the sum rule to separate the terms.✓ Proved
  3. \[ = \frac{d}{d x} 3 x \ln{\left(5 x - 1 \right)} - \frac{d}{d x} \frac{3 \ln{\left(5 x - 1 \right)}}{5} - 3 \]
    constantDifferentiate the linear term 3*x.✓ Proved
  4. \[ = 3 x \frac{d}{d x} \ln{\left(5 x - 1 \right)} + 3 \ln{\left(5 x - 1 \right)} - \frac{d}{d x} \frac{3 \ln{\left(5 x - 1 \right)}}{5} - 3 \]
    productApply the product rule to the first term.✓ Proved
  5. \[ = \frac{3 x \frac{d}{d x} \left(5 x - 1\right)}{5 x - 1} + 3 \ln{\left(5 x - 1 \right)} - \frac{d}{d x} \frac{3 \ln{\left(5 x - 1 \right)}}{5} - 3 \]
    chainApply the chain rule to the logarithm.✓ Proved
  6. \[ = \frac{15 x}{5 x - 1} + 3 \ln{\left(5 x - 1 \right)} - \frac{d}{d x} \frac{3 \ln{\left(5 x - 1 \right)}}{5} - 3 \]
    derivative algebraDifferentiate the inner function 5*x - 1. Simplify the product in the second term.✓ Proved
  7. \[ = \frac{15 x}{5 x - 1} + 3 \ln{\left(5 x - 1 \right)} - 3 - \frac{3}{5 x - 1} \]
    constant-multiple algebraPull out the constant 3/5 from the derivative. Simplify the last term.✓ Proved
  8. \[ = 3 \ln{\left(5 x - 1 \right)} - 3 + \frac{15 x - 3}{5 x - 1} \]
    algebraCombine the terms with the common denominator 5*x - 1.✓ Proved
  9. \[ = 3 \ln{\left(5 x - 1 \right)} \]
    algebra algebra algebra simplifyExpress the constant 3 with the common denominator. Distribute the 3 in the numerator. Combine like terms in the numerator. Simplify the final expression.✓ Proved
Answer \( 3 \ln{\left(5 x - 1 \right)} \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 5*x - 1 = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 5*x - 1 = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 5*x - 1 = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 5*x - 1 = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 5*x - 1 = 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 5*x - 1 = 0
11✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 5*x - 1 = 0
12✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
13✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
14✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies differentiation rules one at a time and uses valid labels from the fixed vocabulary. The algebraic simplification steps are sound and lead to the correct result.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-09-28 — The solution correctly applies differentiation rules one at a time and uses valid labels from the fixed vocabulary. The algebraic simplification steps are sound and lead to the correct result.
  • gpt-oss:20b: pass 2026-09-28
  • qwen3.6:27b-mlx: pass 2026-09-28 — The solution correctly applies differentiation rules one at a time and uses valid labels from the fixed vocabulary. The algebraic simplification steps are sound and lead to the correct final answer.
  • gpt-oss:20b: pass 2026-09-28

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-09-28 with SymPy 1.14.0.