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Derivative of \( \displaystyle 2 x \left(25 x^{2} + 15 x + 3\right) \)

Problem 2.1087 · hard Video

Differentiate \( \displaystyle f(x) = 2 x \left(25 x^{2} + 15 x + 3\right) \).
  1. \[ \frac{d}{d x} 2 x \left(25 x^{2} + 15 x + 3\right) \]
    derivativeStart with the derivative of the function.✓ Proved
  2. \[ = 2 x \frac{d}{d x} \left(25 x^{2} + 15 x + 3\right) + \left(25 x^{2} + 15 x + 3\right) \frac{d}{d x} 2 x \]
    productApply the product rule.✓ Proved
  3. \[ = 50 x^{2} + 2 x \frac{d}{d x} \left(25 x^{2} + 15 x + 3\right) + 30 x + 6 \]
    constant-multipleFactor out the constant 2 from the first term.✓ Proved
  4. \[ = 50 x^{2} + 2 x \left(\frac{d}{d x} 3 + \frac{d}{d x} 15 x + \frac{d}{d x} 25 x^{2}\right) + 30 x + 6 \]
    sumApply the sum rule to the second term.✓ Proved
  5. \[ = 50 x^{2} + 2 x \left(50 x + 15\right) + 30 x + 6 \]
    derivative simplifyDifferentiate each term inside the parentheses. Simplify the expression by removing the zero.✓ Proved
  6. \[ = 150 x^{2} + 60 x + 6 \]
    algebra simplifyDistribute the terms. Combine like terms.✓ Proved
Answer \( 6 \left(5 x + 1\right)^{2} \)
Top: the graph of f = 2x·(25x² + 15x + 3). A tangent line slides along it, and its slope is plotted below as it goes, tracing f' = 50x² + 2x·(50x + 15) + 30x + 6.

Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: fail (error) — Step 3 incorrectly factors out the constant 2 from the first term, dropping the factor of x and changing the expression from 2*x*(25*x**2+15*x+3) to 2*(25*x**2+15*x+3). This applies more than one rule at once and results in an algebraically incorrect intermediate expression.
  • qwen3.6:27b-mlx: pass — The solution correctly applies the product rule, sum rule, and power rule in distinct steps. The final simplification is algebraically correct and matches the stated answer.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-09-29 — The solution correctly applies the product rule, sum rule, and power rule in distinct steps. The final simplification is algebraically correct and matches the stated answer.
  • gpt-oss:20b: fail (error) 2026-09-29 — Step 3 incorrectly factors out the constant 2 from the first term, dropping the factor of x and changing the expression from 2*x*(25*x**2+15*x+3) to 2*(25*x**2+15*x+3). This applies more than one rule at once and results in an algebraically incorrect intermediate expression.
  • qwen3.6:27b-mlx: pass 2026-09-28 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint and using valid labels from the fixed vocabulary.
  • gpt-oss:20b: pass 2026-09-28
  • qwen3.6:27b-mlx: pass 2026-09-28
  • gpt-oss:20b: fail (style) 2026-09-28 — Step 7 distributes both products in one line, applying two algebraic expansions at once, violating the rule that each step must change only one thing.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-09-29 with SymPy 1.14.0.