∫Calc Practice

Derivative of \( \displaystyle \left(2 x\right)^{\cos{\left(2 x \right)}} \)

Problem 2.1053 · hard

Differentiate \( \displaystyle f(x) = \left(2 x\right)^{\cos{\left(2 x \right)}} \).
  1. \[ \frac{d}{d x} \left(2 x\right)^{\cos{\left(2 x \right)}} \]
    derivativeStart with the derivative of the function.✓ Proved
  2. \[ = \frac{d}{d x} e^{\ln{\left(2 x \right)} \cos{\left(2 x \right)}} \]
    rewriteRewrite the base-exponent expression using the exponential and logarithm.≈ Checked numerically
  3. \[ = e^{\ln{\left(2 x \right)} \cos{\left(2 x \right)}} \frac{d}{d x} \ln{\left(2 x \right)} \cos{\left(2 x \right)} \]
    chainApply the chain rule.✓ Proved
  4. \[ = \left(\ln{\left(2 x \right)} \frac{d}{d x} \cos{\left(2 x \right)} + \cos{\left(2 x \right)} \frac{d}{d x} \ln{\left(2 x \right)}\right) e^{\ln{\left(2 x \right)} \cos{\left(2 x \right)}} \]
    productApply the product rule to the inner expression.✓ Proved
  5. \[ = \left(- 2 \ln{\left(2 x \right)} \sin{\left(2 x \right)} + \frac{\cos{\left(2 x \right)}}{x}\right) e^{\ln{\left(2 x \right)} \cos{\left(2 x \right)}} \]
    derivative algebraDifferentiate the individual terms. Simplify the expression inside the parentheses.✓ Proved
  6. \[ = \left(2 x\right)^{\cos{\left(2 x \right)}} \left(- 2 \ln{\left(2 x \right)} \sin{\left(2 x \right)} + \frac{\cos{\left(2 x \right)}}{x}\right) \]
    simplifyConvert back to the original base-exponent form.≈ Checked numerically
Answer \( \left(2 x\right)^{\cos{\left(2 x \right)}} \left(- 2 \ln{\left(2 x \right)} \sin{\left(2 x \right)} + \frac{\cos{\left(2 x \right)}}{x}\right) \)

✓ Nihil obstat Lines: 6 proved, 2 checked numerically. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2≈ Checked numericallysympy 1.14.0sympy 1.14.0: simplify left ((2*x)**cos(2*x)*(-2*x*log(2*x)*sin(2*x) + cos(2*x)) + (2*x*log(2*x)*sin(2*x) - cos(2*x))*exp(log(2*x)*cos(2*x)))/x; numeric agreement only, at 24 of 24 sampled points
log is undefined for non-positive arguments
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x = 0
7≈ Checked numericallysympy 1.14.0sympy 1.14.0: simplify left ((2*x)**cos(2*x)*(2*x*log(2*x)*sin(2*x) - cos(2*x)) + (-2*x*log(2*x)*sin(2*x) + cos(2*x))*exp(log(2*x)*cos(2*x)))/x; numeric agreement only, at 24 of 24 sampled points
log is undefined for non-positive arguments
undefined where x = 0
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x = 0
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies the exponential-logarithmic rewrite, chain rule, and product rule in distinct steps. All labels accurately reflect the operations performed.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-09-28 — The solution correctly applies the exponential-logarithmic rewrite, chain rule, and product rule in distinct steps. All labels accurately reflect the operations performed.
  • gpt-oss:20b: pass 2026-09-28
  • qwen3.6:27b-mlx: pass 2026-09-28
  • gpt-oss:20b: pass 2026-09-28

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-09-28 with SymPy 1.14.0.