∫Calc Practice
Home›Calculus 1›Chain rule›Problem 2.1034

Derivative of \( \displaystyle \operatorname{atan}{\left(\cot{\left(3 x \right)} + \csc{\left(3 x \right)} \right)} \)

Problem 2.1034 · hard Beautiful Video

Differentiate \( \displaystyle f(x) = \operatorname{atan}{\left(\cot{\left(3 x \right)} + \csc{\left(3 x \right)} \right)} \).
  1. \[ \frac{d}{d x} \operatorname{atan}{\left(\cot{\left(3 x \right)} + \csc{\left(3 x \right)} \right)} \]
    derivativeStart with the derivative of the function.✓ Proved
  2. \[ = \frac{\frac{d}{d x} \left(\cot{\left(3 x \right)} + \csc{\left(3 x \right)}\right)}{\left(\cot{\left(3 x \right)} + \csc{\left(3 x \right)}\right)^{2} + 1} \]
    chainApply the chain rule for the arctangent function.✓ Proved
  3. \[ = \frac{\frac{d}{d x} \cot{\left(3 x \right)} + \frac{d}{d x} \csc{\left(3 x \right)}}{\left(\cot{\left(3 x \right)} + \csc{\left(3 x \right)}\right)^{2} + 1} \]
    sumApply the sum rule to the inner derivative.✓ Proved
  4. \[ = \frac{- 3 \csc^{2}{\left(3 x \right)} + \frac{d}{d x} \csc{\left(3 x \right)}}{\left(\cot{\left(3 x \right)} + \csc{\left(3 x \right)}\right)^{2} + 1} \]
    derivativeDifferentiate the cotangent term.✓ Proved
  5. \[ = \frac{- 3 \cot{\left(3 x \right)} \csc{\left(3 x \right)} - 3 \csc^{2}{\left(3 x \right)}}{\left(\cot{\left(3 x \right)} + \csc{\left(3 x \right)}\right)^{2} + 1} \]
    derivativeDifferentiate the cosecant term.✓ Proved
  6. \[ = - \frac{3 \left(\cot{\left(3 x \right)} + \csc{\left(3 x \right)}\right) \csc{\left(3 x \right)}}{\left(\cot{\left(3 x \right)} + \csc{\left(3 x \right)}\right)^{2} + 1} \]
    algebra algebraFactor out common terms in the numerator. Combine the expression into a single fraction.✓ Proved
  7. \[ = - \frac{3 \left(\cot{\left(3 x \right)} + \csc{\left(3 x \right)}\right) \csc{\left(3 x \right)}}{\cot^{2}{\left(3 x \right)} + 2 \cot{\left(3 x \right)} \csc{\left(3 x \right)} + \csc^{2}{\left(3 x \right)} + 1} \]
    algebraExpand the squared term in the denominator.✓ Proved
  8. \[ = - \frac{3 \left(\cot{\left(3 x \right)} + \csc{\left(3 x \right)}\right) \csc{\left(3 x \right)}}{2 \cot{\left(3 x \right)} \csc{\left(3 x \right)} + 2 \csc^{2}{\left(3 x \right)}} \]
    algebra simplifyUse the identity cot(3*x)**2 = csc(3*x)**2 - 1. Simplify the denominator by combining like terms.✓ Proved
  9. \[ = - \frac{3}{2} \]
    algebra simplify simplifyFactor the denominator. Cancel the common factor (csc(3*x) + cot(3*x)). Cancel the common factor csc(3*x) to get the final result.✓ Proved
Answer \( - \frac{3}{2} \)
Top: the graph of f = atan(cot(3x) + csc(3x)). A tangent line slides along it, and its slope is plotted below as it goes, tracing f' = (-3cot(3x)² - 3cot(3x)·csc(3x) - 3)/((cot(3x) + csc(3x))² + 1).
Mind the domain. The answer is also defined at points where f(x) is not. Substituting there gives a number that is not a slope of f.

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where (cot(3*x) + csc(3*x))**2 + 1 = 0
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where (cot(3*x) + csc(3*x))**2 + 1 = 0
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where (cot(3*x) + csc(3*x))**2 + 1 = 0
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where (cot(3*x) + csc(3*x))**2 + 1 = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where (cot(3*x) + csc(3*x))**2 + 1 = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where (cot(3*x) + csc(3*x))**2 + 1 = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where (cot(3*x) + csc(3*x))**2 + 1 = 0
undefined where cot(3*x)**2 + 2*cot(3*x)*csc(3*x) + csc(3*x)**2 + 1 = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where cot(3*x)**2 + 2*cot(3*x)*csc(3*x) + csc(3*x)**2 + 1 = 0
undefined where 2*cot(3*x)*csc(3*x) + 2*csc(3*x)**2 = 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where 2*cot(3*x)*csc(3*x) + 2*csc(3*x)**2 = 0
11✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
csc has poles at multiples of pi
cot has poles at multiples of pi
undefined where 2*cot(3*x)*csc(3*x) + 2*csc(3*x)**2 = 0
12✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
13✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-09-28
  • gpt-oss:20b: pass 2026-09-28
  • qwen3.6:27b-mlx: pass 2026-09-27 — The solution correctly applies the chain rule, sum rule, and standard trigonometric derivatives. The algebraic simplification steps are valid, and the labels used are consistent with the provided vocabulary.
  • gpt-oss:20b: pass 2026-09-27
  • qwen3.6:27b-mlx: pass 2026-09-27
  • gpt-oss:20b: pass 2026-09-27

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-09-28 with SymPy 1.14.0.