Exponential and logarithmic equations
Problem 13.293 · medium
Solve \( \displaystyle 10^{2 x} - 5 \cdot 10^{x} + 6 = 0 \) exactly.
- Let u = 10ˣ: u² − 5u + 6 = 0 factors as (u − 2)(u − 3) = 0.Reviewed
- \[ \left. 10^{2 x} - 5 \cdot 10^{x} + 6 \right|_{\substack{ x=\frac{\ln{\left(2 \right)}}{\ln{\left(10 \right)}} }} = 0 \]x = log(2)/log(10) satisfies the equation.✓ Proved
- \[ \left. 10^{2 x} - 5 \cdot 10^{x} + 6 \right|_{\substack{ x=\frac{\ln{\left(3 \right)}}{\ln{\left(10 \right)}} }} = 0 \]x = log(3)/log(10) satisfies the equation.✓ Proved
Answer \( x = \frac{\ln{\left(2 \right)}}{\ln{\left(10 \right)}},\ \frac{\ln{\left(3 \right)}}{\ln{\left(10 \right)}} \)
✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | Newton's method over [−20, 20] finds exactly the claimed real roots |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly identifies the substitution and roots, and verifies them. Although it omits the explicit step of solving for x from u=2 and u=3, the verification steps confirm the stated answer is correct.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-18 — The solution correctly identifies the substitution and roots, and verifies them. Although it omits the explicit step of solving for x from u=2 and u=3, the verification steps confirm the stated answer is correct.gpt-oss:20b: pass 2026-10-18qwen3.6:27b-mlx: pass 2026-10-16 — The solution correctly identifies the substitution, solves the quadratic, and verifies the resulting exact solutions.gpt-oss:20b: pass 2026-10-16qwen3.6:27b-mlx: pass 2026-10-15 — The solution correctly identifies the substitution, solves the resulting quadratic, and provides the exact logarithmic forms for x. The verification steps confirm the roots.gpt-oss:20b: pass 2026-10-15
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/log_exp_equations, checked 2026-10-18 with SymPy 1.14.0.