∫Calc Practice

Solving trigonometric equations

Problem 13.255 · medium

Solve \( \displaystyle 2 \cos^{2}{\left(\theta \right)} + 2 \cos{\left(\theta \right)} = 0 \) for \( \displaystyle 0 \le \theta < 2\pi \).
  1. \[ 2 \cos^{2}{\left(\theta \right)} + 2 \cos{\left(\theta \right)} = \left(2 \cos{\left(\theta \right)} + 2\right) \cos{\left(\theta \right)} \]
    Factor as a quadratic in cos θ.✓ Proved
  2. Set each factor to zero; then find every angle in [0, 2π) with those values.
  3. \[ \left. 2 \cos^{2}{\left(\theta \right)} + 2 \cos{\left(\theta \right)} \right|_{\substack{ \theta=\frac{\pi}{2} }} = 0 \]
    θ = pi/2 works.✓ Proved
  4. \[ \left. 2 \cos^{2}{\left(\theta \right)} + 2 \cos{\left(\theta \right)} \right|_{\substack{ \theta=\pi }} = 0 \]
    θ = pi works.✓ Proved
  5. \[ \left. 2 \cos^{2}{\left(\theta \right)} + 2 \cos{\left(\theta \right)} \right|_{\substack{ \theta=\frac{3 \pi}{2} }} = 0 \]
    θ = 3*pi/2 works.✓ Proved
Answer \( \theta = \frac{\pi}{2},\ \pi,\ \frac{3 \pi}{2} \)

Lines: 4 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Not checked—a sentence; read, not computed
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0Newton's method from 1440 starting points finds exactly 3 roots in [0, 2π), the same ones

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: fail (error) — The solution verifies that the listed values are roots but fails to demonstrate that they are the *only* solutions in the interval [0, 2π). Specifically, it omits the derivation from the factors (e.g., cos(θ) = 0 or cos(θ) = -1) to the specific angles, leaving the completeness of the solution set unproven.
Every verdict on record (6)
  • qwen3.6:27b-mlx: fail (error) 2026-10-18 — The solution verifies that the listed values are roots but fails to demonstrate that they are the *only* solutions in the interval [0, 2π). Specifically, it omits the derivation from the factors (e.g., cos(θ) = 0 or cos(θ) = -1) to the specific angles, leaving the completeness of the solution set unproven.
  • gpt-oss:20b: pass 2026-10-18
  • qwen3.6:27b-mlx: fail (error) 2026-10-16 — The solution verifies that the stated answers are solutions but fails to demonstrate that they are the *only* solutions in the given interval. It omits the step of solving cos(theta) = 0 and cos(theta) = -1 to derive the values, leaving the completeness of the solution set unproven.
  • gpt-oss:20b: pass 2026-10-16
  • qwen3.6:27b-mlx: fail (error) 2026-10-15 — The solution is incomplete because it only verifies the proposed answers rather than deriving them. It fails to explicitly solve the factored equation cos(θ)(cos(θ) + 1) = 0 to show that cos(θ) = 0 and cos(θ) = -1 are the only cases, and thus that no other solutions exist in the interval.
  • gpt-oss:20b: pass 2026-10-15

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/trig_equations, checked 2026-10-18 with SymPy 1.14.0.