Green's theorem
Problem 12.97 · easy
Use Green's theorem to evaluate \( \displaystyle \oint_C (x y)\,dx + (x^{2})\,dy \), where C is the boundary of the rectangle \( \displaystyle [0, 1] \times [0, 2] \), counterclockwise.
- Green's theorem: ∮ P dx + Q dy = ∬ (∂Q/∂x − ∂P/∂y) dA.
- \[ \frac{d}{d x} x^{2} - \frac{\partial}{\partial y} x y = x \]∂Q/∂x − ∂P/∂y.✓ Proved
- \[ \int\limits_{0}^{2}\int\limits_{0}^{1} x\, dx\, dy = 1 \]Integrate over the rectangle.✓ Proved
Answer \( 1 \)
Lines: 2 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Not checked | — | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the line integral around the four edges, done directly, gives the same value |
Reviewers
gpt-oss:20b: fail (error) — The integrand in the double integral should be x (from ∂Q/∂x−∂P/∂y), but the solution integrates 1 over the rectangle, leading to an incorrect value.qwen3.6:27b-mlx: pass — The solution correctly applies Green's Theorem, computes the partial derivatives accurately, and evaluates the double integral over the specified rectangular region.
Every verdict on record (4)
qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly applies Green's Theorem, computes the partial derivatives accurately, and evaluates the double integral over the specified rectangular region.gpt-oss:20b: fail (error) 2026-09-26 — The integrand in the double integral should be x (from ∂Q/∂x−∂P/∂y), but the solution integrates 1 over the rectangle, leading to an incorrect value.qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly applies Green's theorem, computes the partial derivatives accurately, and evaluates the double integral over the specified rectangular region.gpt-oss:20b: fail (error) 2026-09-26 — The integrand in the double integral should be x (since ∂Q/∂x−∂P/∂y = x), but the solution integrates 1 over the rectangle, yielding 2 instead of the correct value 1.
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/greens_theorem, checked 2026-09-26 with SymPy 1.14.0.