Line integrals and work
Problem 12.8 · medium
Find the work done by \( \displaystyle \mathbf{F} = \langle - y, x \rangle \) along the line segment from (0, 0) to (2, 3).
- Parametrize: r(t) = ⟨2*t, 3*t⟩ for 0 ≤ t ≤ 1.Reviewed
- \[ \left[\begin{matrix}\frac{d}{d t} 2 t\\\frac{d}{d t} 3 t\end{matrix}\right] = \left[\begin{matrix}2\\3\end{matrix}\right] \]r'(t).✓ Proved
- \[ 0 \]F(r(t)) · r'(t).Reviewed
- \[ \int\limits_{0}^{1} 0\, dt = 0 \]W = ∫ F · dr.✓ Proved
Answer \( 0 \)
✓ Nihil obstat Lines: 2 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | both sides are the same expression: the line states a value, and the working that produced it is not on the line |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | a 20,000-chord polygon along the path gives the same work |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The parametrization is correct for the line segment. The calculation of F(r(t)) = <-3t, 2t> and r'(t) = <2, 3> yields a dot product of -6t + 6t = 0. The integral of 0 is 0. The solution is sound.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-09-28 — The parametrization is correct for the line segment. The calculation of F(r(t)) = <-3t, 2t> and r'(t) = <2, 3> yields a dot product of -6t + 6t = 0. The integral of 0 is 0. The solution is sound.gpt-oss:20b: pass 2026-09-28qwen3.6:27b-mlx: pass 2026-09-27 — The parametrization is correct for the line segment from (0,0) to (2,3). The calculation of the dot product F(r(t)) · r'(t) resulting in 0 is correct, leading to the correct work of 0.gpt-oss:20b: pass 2026-09-27qwen3.6:27b-mlx: pass 2026-09-26 — The parametrization is correct for the line segment. The dot product calculation F(r(t)) · r'(t) = (-3t)(2) + (2t)(3) = -6t + 6t = 0 is correct. The integral of 0 is 0. The solution is sound.gpt-oss:20b: pass 2026-09-26
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/line_integral_work, checked 2026-10-13 with SymPy 1.14.0.