Stokes' theorem
Problem 12.372 · hard
Use Stokes' theorem to evaluate \( \displaystyle \oint_C \mathbf F \cdot d\mathbf r \) for \( \displaystyle \mathbf F = \left\langle y^{2}, x, z^{2} \right\rangle \), where \( \displaystyle C \) is the circle \( \displaystyle x^2 + y^2 = 9 \) in the plane \( \displaystyle z = 0 \), counterclockwise seen from above.
- Take S to be the flat disk the circle bounds, with upward normal k. Stokes: ∮_C F · dr = ∬_S (curl F) · k dA.Reviewed
- \[ \left[\begin{matrix}- \frac{d}{d z} x + \frac{d}{d y} z^{2}\\\frac{d}{d z} y^{2} - \frac{d}{d x} z^{2}\\\frac{d}{d x} x - \frac{d}{d y} y^{2}\end{matrix}\right] = \left[\begin{matrix}0\\0\\1 - 2 y\end{matrix}\right] \]curl F.✓ Proved
- \[ \int\limits_{0}^{2 \pi}\int\limits_{0}^{3} r \left. 1 - 2 y \right|_{\substack{ x=r \cos{\left(\theta \right)}\\ y=r \sin{\left(\theta \right)} }}\, dr\, d\theta = 9 \pi \]The k-component of the curl over the disk, in polar coordinates.✓ Proved
- \[ \int\limits_{0}^{2 \pi} \left(- 27 \sin^{3}{\left(t \right)} + 9 \cos^{2}{\left(t \right)}\right)\, dt = 9 \pi \]The circulation computed directly around C agrees.✓ Proved
Answer \( 9 \pi \)
✓ Nihil obstat Lines: 3 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | F · Δr summed around a 20,000-sided polygon on the circle |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly applies Stokes' theorem, computes the curl, and evaluates the surface integral over the disk. The orientation is consistent with the problem statement.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly applies Stokes' theorem, computes the curl, and evaluates the surface integral over the disk. The orientation is consistent with the problem statement.gpt-oss:20b: pass 2026-10-17qwen3.6:27b-mlx: pass 2026-10-15 — The solution correctly applies Stokes' Theorem. The setup of the surface integral is correct, and the direct line integral calculation serves as a valid verification. No errors or misleading statements are present.gpt-oss:20b: pass 2026-10-15qwen3.6:27b-mlx: pass 2026-10-14 — The solution correctly applies Stokes' Theorem, computes the curl and surface integral accurately, and verifies the result with a direct line integral. The setup and logic are sound.gpt-oss:20b: pass 2026-10-14
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/stokes_theorem, checked 2026-10-17 with SymPy 1.14.0.