Line integrals and work
Problem 12.37 · medium
Find the work done by \( \displaystyle \mathbf{F} = \langle y^{2}, 2 x \rangle \) along the unit circle, counterclockwise.
- Parametrize: r(t) = ⟨cos(t), sin(t)⟩ for 0 ≤ t ≤ 2*pi.Reviewed
- \[ \left[\begin{matrix}\frac{d}{d t} \cos{\left(t \right)}\\\frac{d}{d t} \sin{\left(t \right)}\end{matrix}\right] = \left[\begin{matrix}- \sin{\left(t \right)}\\\cos{\left(t \right)}\end{matrix}\right] \]r'(t).✓ Proved
- \[ - \sin^{3}{\left(t \right)} + 2 \cos^{2}{\left(t \right)} \]F(r(t)) · r'(t).Reviewed
- \[ \int\limits_{0}^{2 \pi} \left(- \sin^{3}{\left(t \right)} + 2 \cos^{2}{\left(t \right)}\right)\, dt = 2 \pi \]W = ∫ F · dr.✓ Proved
Answer \( 2 \pi \)
✓ Nihil obstat Lines: 2 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | both sides are the same expression: the line states a value, and the working that produced it is not on the line |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | a 20,000-chord polygon along the path gives the same work |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The parametrization, dot product, and integration are all correct. The solution is sound.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-09-28 — The parametrization, dot product, and integration are all correct. The solution is sound.gpt-oss:20b: pass 2026-09-28qwen3.6:27b-mlx: pass 2026-09-27 — The parametrization, dot product calculation, and integration are all correct. The solution is sound.gpt-oss:20b: pass 2026-09-27qwen3.6:27b-mlx: pass 2026-09-26 — The parametrization is correct for the unit circle counterclockwise. The dot product and integration steps are algebraically verified and yield the correct result.gpt-oss:20b: pass 2026-09-26
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/line_integral_work, checked 2026-10-13 with SymPy 1.14.0.